Answer:
The initial temperature of the object was 37.6
Step-by-step explanation:
we have
where
f(t) represent the temperature of the object in degree Celsius
t is the time in minutes
Find the value of the constant C
we have the ordered pair (4,35)
substitute in the equation and solve for C
Find the initial value of the object
we know that
The initial temperature is the value of f(t) when the value of t is equal to zero
so
For t=0
therefore
The initial temperature of the object was 37.6 (I not include units)
Step-by-step explanation:
<h3>=80°-15°</h3><h3>=65°</h3>
please mark this answer as brainlist
Edited 2018-03-09 07:49
Given unit circle, so radius=1.
We calculate lengths of vertical segments, with the help of Pythagoras Theorem, based on a right triangle radiating from circle centre O, and hypotenuse from O to a point on the circumference.
AO=1 (given unit circle)
BB'=sqrt(1^2-0.25^2)=0.968246
CC'=sqrt(1^2-0.5^2)=0.866025
DD'=sqrt(1^2-0.75^2)=0.661438
EE'=0
Now we proceed to calculate the segments approximating the arc. Again, we use a right triangle in which the hypotenuse is the segment joining two points on the circumference. The height is the difference between the two vertical segments, and the base is 0.25 for all four segments.
AB=sqrt((AO-BB)^2+0.25^2)=0.252009BC=sqrt((BB-CC)^2+0.25^2)=0.270091CD=sqrt((CC-DD)^2+0.25^2)=0.323042DE=sqrt((DD-0)^2+0.25^2)=0.7071068
giving a total estimation of the arc length
approximation of arc=AB+BC+CD+DE=1.55225
Answer:
two irrational solutions
Step-by-step explanation:
you can use the quadratic formula: (b ± √b²- 4ac)÷2a
a = 5, b = -2, c = 6
= [2 ± √(-2²)-4(5)(6)] ÷ 2(5)
= (2 ± √4-120) / 10
two complex solutions: (2+√-116)/10, (2-√-116)/10
Answer
Top one
Step by step explanation
