-11.7 i think plz give feed back
Answer:
Step-by-step explanation:
Given a sample M(t)
M(t) = 120 • ( 81 / 625)^t
When is the fraction of the mass decay to 3/5 of it's mass
Generally
M(t) = Mo•(k^t)
The original mass is 120
Mo = 120
So, we want to find time when it decay to 3/5 of it's original mas
M = 3/5 × 120
M = 72
Then,
M(t) = 120 • ( 81 / 625)^t
72 = 120 • ( 81 / 625)^t
72 / 120 = ( 81 / 625)^t
0.6 = ( 81 / 625)^t
Take natural logarithmic of both sides
In(0.6) = In(81/625)^t
In(0.6) = t•In(81/625)
t = In(0.6) / In(81/625)
t = In(0.6) / In(0.1296)
t = 0.25 monthly
t = ¼ monthly
Answer:
<h2>1/11</h2>
Step-by-step explanation:
even #s between (or including) 1 and 12:
2, 4, 6, 8, 10, 12
there are 6
6/12 for the first one
5/11 for the second one (one even # less)
4/10 for the third one
To find the probability of picking three even numbers from 1 to 12 in a row three times:
multiply the probabilities together:
(6/12)*(5/11)*(4/10)=(24/120)*(5/11)=(12/60)*(5/11)=(1/5)*(5/11)=5/55=1/11
€800 with 50% = €400. €600 with 30%=€420