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ivann1987 [24]
3 years ago
12

Neptune’s average distance from the sun is 4.503 x 10e9 km. Mercury’s average distance from the sun is 5.791 x10e9 km.about how

many times farther from the sun is Neptune than mercury?
Mathematics
1 answer:
Igoryamba3 years ago
4 0

Answer:

77.76 times

Step-by-step explanation:

The average distance of Neptune  from the sun

= 4.503  ×  10 ⁹  k m .

and Mercury  =  5.791  ×  10 ⁷ k m .

Hence neptune is (  4.503  ×  10 ⁹) ÷ (5.791 × 10 ⁷  ) times farther from the sun than mercury

i.e.(  \frac{4.503}{5.791} )  × 10⁹⁻⁷ times

=   0.7776  ×  10 ² times

=   77.76  times.

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Hey there! :)

Answer:

y = 5x + 10

Step-by-step explanation:

From the information given, we can derive the points (-2, 0) and (0, 10). Find the slope using the slope formula:

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The equation in slope-intercept form is y = mx + b. We were already given the b value, or y-intercept as y = 10. Therefore:

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