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inessss [21]
3 years ago
10

If Jim was suppose to be at work at 8:45 but did not get there until 9:15. How late in minutes is he?

Mathematics
1 answer:
gavmur [86]3 years ago
3 0
30 minutes 45-15=30 ok
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What is 156 divided by 12?
madreJ [45]
The answer for your question is thirteen
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3 years ago
A study was recently conducted to estimate the mean cholesterol for adult males over the age of 55 years. From a random sample o
Komok [63]

Answer:  Correct critical value = 2.2622

Step-by-step explanation:

Confidence interval for population mean when population standard deviation is unknown:

\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}} , where \overline{x} = sample mean, n= sample size, s= sample standard deviation, t_{\alpha/2} = two-tailed t value.

As per given: n= 10

degree of freedom : df = n-1=9

\overline{x}=242.6\\\\s=73.33\\\\\alpha=5\%=0.05

Critical t-value : t_{\alpha/2,df}=t_{0.05/2,9}=t_{0.025,9}=2.2622

So, the 95 percent confidence interval estimate for the​ mean :

242.6\pm (2.2622)\dfrac{73.33}{\sqrt{10}}\\\\=242.6\pm (2.2622)(23.19)\\\\\approx242.6\pm52.46\\\\=(242.6-52.46,\ 242.6+52.46)\\\\=(190.14,\ 295.06)

The 95 percent confidence interval estimate for the​ mean:(190.14, 295.06)

8 0
3 years ago
Find two irrational numbers between 0.31 and 0.32
labwork [276]

The answer could be .317

(not could be as in I don't know but could be as is it's an option)

5 0
2 years ago
At the beginning of an environmental study, a forest covered an area of 1500 km. Since then, this area has decreased by 7.25% ea
WITCHER [35]

\qquad \textit{Amount for Exponential Decay} \\\\ y=P(1 - r)^t\qquad \begin{cases} y=\textit{current amount}\\ P=\textit{initial amount}\dotfill &1500\\ r=rate\to 7.25\%\to \frac{7.25}{100}\dotfill &0.0725\\ t=\textit{elapsed time}\dotfill &t\\ \end{cases} \\\\\\ y=1500(1-0.0725)^t\implies y=1500(0.9275)^t

5 0
2 years ago
I don’t understand what to do on these question, some help would be nice (trigonometry)
Bumek [7]

Step-by-step explanation:

> find the angle of center circle:

cos~¹ 5/(5+12) = cos~¹ 5/17 = 72°

so the sector area of the shaded

region =

(360-72)/360 × 3.14 × 5²

= 288/360 × 78.5

= 62.8

> the height of triangle (red Line) =

4×tan 72° = 4× 3.078 = 12.31

the height of pyramid (green

Line) = √12.31²-8.5² =√74.16

= 8.61

so the volume of pyramid =

⅓×(17×8)×8.61 = 390.32

8 0
2 years ago
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