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Fed [463]
3 years ago
7

Help!!! ---- The graph of a function is a line that passes through the points (1,4), (3,8), and (6,y). What is the value of y?

Mathematics
1 answer:
natima [27]3 years ago
5 0

Answer:

y = 14

Step-by-step explanation:

First find the slope of the line. To find the slope of the line, use the slope formula:

m = \frac{y_2-y_1}{x_2-x_1} = \frac{8-4}{3-1} =\frac{4}{2}=2

The slope of the line is 2.

Repeat this same process instead with points (1,4) and (6,y). Substitute m = 2.

2 = \frac{y-4}{6-1} \\\\ 2=\frac{y-4}{5}\\\\ 10=y-4\\\\14b= y

So y = 14.

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The image shows a dust mite as seen under a microscope. The scale of the drawing to dust is 100:1
hoa [83]

The actual length of the dust termite observed under the microscope is 1.5 mm

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HEY YA'LL 30 PTS FOR 1 PROBLEM!<br> Given: m∠EYL=1/3 the measure of arc EHL<br> Find: m∠EYL.
GarryVolchara [31]

Answer:

45

Step-by-step explanation:

Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.

m<EYL = (1/2)(m(arc)EVL - m(arc)EHL)      Eq. 1

The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.

m(arc)EVL + m(arc)EHL = 360

m(arc)EVL = 360 - m(arc)EHL      Eq. 2

We are given this:

m<EYL = (1/3)m(arc)EHL       Eq. 3

Substitute equations 2 and 3 into equation 1.

(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]

Now we have a single unknown, m(arc)EHL, so we solve for it.

2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]

2m(arc)EHL = 1080 - 6m(arc)EHL

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m(arc)EHL = 135

Substitute the arc measure just found in Equation 3.

m<EYL = (1/3)m(arc)EHL

m<EYL = (1/3)(135)

m<EYL = 45

5 0
3 years ago
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