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zhenek [66]
3 years ago
6

For the following cylinder, what is the area of the two bases in square centimeters?

Mathematics
1 answer:
Bezzdna [24]3 years ago
8 0
Cylinder formula is 2pi(r)^2 + 2pi(r)h

2pi(0.25)^2 + 2pi(0.25)(1)

Chuck that in calculator and evaluate
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Celine is estimating the number of tiles in a mosaic. There are 7 different colors, and 472 tiles of each color. There are also
ValentinkaMS [17]

Answer:

3,400 tiles

Step-by-step explanation:

Since there is 472 tiles of each 7 colors,

Multiply 472 by 7 to get 3,304

Then you would add the 96 blank tiles to get exactly

3.400 tiles.

8 0
3 years ago
PLEASE HELP!!! <br>What is mDBC?​
defon

Answer:

i dont get the question sorry

Step-by-step explanation:

7 0
3 years ago
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Jimmy is buying 2 pairs of pants that cost $14.50 each. There is a 7.5% sales tax What is the total Jimmy will pay for the pants
dangina [55]

Answer:

$31.18

Step-by-step explanation:

14.50 x 2 = 29

29 x 0.075 = 2.175

29 + 2.175 = 31.175

Round up to 31.18

5 0
2 years ago
Please answer -w- i really need help lol online school is kinda hard.
Yuliya22 [10]

Answer:

518.7

Step-by-step explanation:

8 0
3 years ago
Please help with imaginary numbers worksheet!
mihalych1998 [28]

Problem 5

<h3>Answer:   6i</h3>

------------------

Explanation:

We have these four identities

  • i^0 = 1
  • i^1 = i
  • i^2 = -1
  • i^3 = -i

Notice how computing i^4 leads us back to 1. So i^4 = i^0. The pattern repeats every 4 terms. So we divide the exponent by 4 and look at the remainder. We ignore the quotient entirely. We can see that 28/4 = 7 remainder 0. Meaning that i^28 = i^0 = 1.

We can think of it like this if you wanted

i^28 = (i^4)^7 = 1^7 = 1

Then the sqrt(-36) becomes 6i

So overall, we end up with the final answer of 6i

=============================================

Problem 6

<h3>Answer:  -3i</h3>

------------------

Explanation:

We'll use the ideas mentioned in problem 5

46/4 = 11 remainder 2

i^46 = i^2 = -1

sqrt(-9) = 3i

The two outside negative signs cancel out, but there's still a negative from -1 we found earlier. So we end up with -3i

In other words, here is one way you could write out the steps

-i^{46}*-\sqrt{-9}\\\\-i^{2}*-3i\\\\i^{2}*3i\\\\-1*3i\\\\-3i\\\\

=============================================

Problem 7

<h3>Answer:   -1</h3>

------------------

Work Shown:

i^10 = i^2 because 10/4 = 2 remainder 2

i^19 = i^3 because 19/4 = 4 remainder 3

i^7 = i^3 because 7/4 = 1 remainder 3

Again, all we care about are the remainders.

i^{10}+i^{19} - i^{7}\\\\i^{2}+i^{3} - i^{3}\\\\i^{2}\\\\-1

=============================================

Problem 8

<h3>Answer:    -1 + i</h3>

------------------

Work Shown:

i^22*i^6 = i^(22+6) = i^28

Earlier in problem 5, we found that i^28 = i^0 = 1

So,

i^1 - \left(i^{22}*i^{6}\right)\\\\i^1 - i^{28}\\\\i^1 - i^{0}\\\\i - 1\\\\-1+i

8 0
2 years ago
Read 2 more answers
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