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nadya68 [22]
3 years ago
7

Rectangle ABCD has coordinates A(0,0), B(0,4), C(3, 0), and D(3, 4). If the

Mathematics
1 answer:
love history [14]3 years ago
7 0

Hello~

The answer is C. (3,0)

Hope this helps!

Ary~

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Nimfa-mama [501]

Answer:

(x,y) - (x,-y)

Step-by-step explanation:

It starts in the top right corner which is positive x and y and then it is reflected across the x-axis which has a positive x and negative y

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Can you help me please?
ExtremeBDS [4]

Answer:

0≤x≤8

Step-by-step explanation:

the domain is basically all the x-values that are applicable to the graph.

Here we can clearly see that the graph starts at x = 0 and ends at x = 8. There are no other possible x-values which is applicable to the graph,

hence the domain is 0≤x≤8

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Write 7/25<br> as a terminating decimal.
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Answer: 0.28

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3 years ago
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The time needed to complete a final examination in a particular college course is normally distributed with a mean of 77 minutes
Komok [63]

Answer:

a. The probability of completing the exam in one hour or less is 0.0783

b. The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. The number of students will be unable to complete the exam in the allotted time is 8

Step-by-step explanation:

a. According to the given we have the following:

The time for completing the final exam in a particular college is distributed normally with mean (μ) is 77 minutes and standard deviation (σ) is 12 minutes

Hence, For X = 60, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=60−77 /12

Z=−1.4167

Using the standard normal table, the probability P(Z≤−1.4167) is approximately 0.0783.

P(Z≤−1.4167)=0.0783

Therefore, The probability of completing the exam in one hour or less is 0.0783.

b. In this case For X = 75, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=75−77 /12

Z=−0.1667

Using the standard normal table, the probability P(Z≤−0.1667) is approximately 0.4338.

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is obtained as follows:

P(60<X<75)=P(Z≤−0.1667)−P(Z≤−1.4167)

=0.4338−0.0783

=0.3555

​

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. In order to compute  how many students you expect will be unable to complete the exam in the allotted time we have to first compute the Z−score of the critical value (X=90) as follows:

Z=  X−μ /σ

Z=90−77 /12

Z​=1.0833

UsING the standard normal table, the probability P(Z≤1.0833) is approximately 0.8599.

Therefore P(Z>1.0833)=1−P(Z≤1.0833)

=1−0.8599

=0.1401

​

Therefore, The number of students will be unable to complete the exam in the allotted time is= 60×0.1401=8.406

The number of students will be unable to complete the exam in the allotted time is 8

6 0
3 years ago
Mrs. Williams needed to make 4 1/2 of fruit salad for a class party.
ziro4ka [17]

Answer:

strawberry=7/8

Step-by-step explanation:

treat strawberry as x

add on proportions

1 1/8+ 3/4+ 1 3/4 + x = 4 1/2

(9+6+14)/8 + x = 9/2

29/8 +x = 9/2

x= 9/2 - 29/8

x= (36-29)/8

x=7/8

3 0
3 years ago
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