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Finger [1]
4 years ago
15

You originally draw a design for an art contest on a 2 inch by 5 inch card. The second phrase of the contest requires the drawin

g to be transferred to an 8.5 inch by 11 inch standard sheet of paper and utilize as much of the space on the paper as possible. You determine the largest size one of the dimensions of your drawing can be is 10.5 inches. What is the length of the other dimension if two drawings are similar? Type your exact answer in the blank without the units and round to the nearest tenth.
Mathematics
1 answer:
Bingel [31]4 years ago
4 0
4.2.
If the 2 inch side was scaled to 10.5 inches the 5 inch side would be scaled by 10.5/2 = 5.25, so would be 25.125 inches which is too big.

So the 10.5 inches is the 5 inch side on the original, and so it 10.5/5 = 2.1 times bigger.

Therefore the smaller side would be 2*2.1/= 4.2 inches.
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Answer:

p_v =P(z>z_{calc})=0.067  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis at 10% of significance.

So then the answer would be

a. true

Step-by-step explanation:

Data given and notation  

\bar X represent the sample mean

\sigma represent the population standard deviation

n sample size  

\mu_o =800 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less or equal than 800 for the null hypothesis:  

Null hypothesis:\mu \leq 800  

Alternative hypothesis:\mu > 800  

The z statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) and we assume that she got a calculated value z_{calc}

P-value

Since is a right tailed test the p value would be:  

p_v =P(z>z_{calc})=0.067  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis at 10% of significance.

So then the answer would be

a. true

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