Ask question

Ask question

All categories

4 years ago

13

60 points for a drawing of the answer for each question

2 answers:

Zigmanuir [339]4 years ago

7 0

For part 2 in segments:
a = ----------
b = ----
c = -------

1) a+b = --------------
2) a-b = ------
3) 2b+a = 2× ----, + ----------
= ------------------
4) a+b+c = ---------------------
5) a+2b-c = 2× ----, + ----------, - -------
= -----------

ollegr [7]4 years ago

7 0

you should only ask for one answer so pls contact me with which answer you would like me to answer

You might be interested in

Nine minus 3 and 3/8

andriy [413]

Answer:6

Step-by-step explanation:

3 0

3 years ago

Write 10 12/5 as an equivalent improper fraction

romanna [79]

10 $\frac{12}{5}$ = $\frac{(10 X 5 ) + 12}{5}$
= $\frac{62}{5}$

8 0

4 years ago

What is 1 6/8 of 16

NARA [144]

Answer:

I'm pretty sure its 28?

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

In 4 years, sravani will be 3 times as old as Makayla is currently. three years ago, sravani was 4 times as old as Makayla was t

77julia77 [94]

X - Sravani
y - Makayala

$x+4=3y\\
x-3=4(y-3)\\\\
x=3y-4\\
x=4y-12+3\\\\
x=3y-4\\
x=4y-9\\\\
3y-4=4y-9\\
4y-3y=-4+9\\
y=5\\\\
x=3\cdot5-4\\
x=15-4\\
x=11$

Sravani - 11
Makayla - 5

3 0

3 years ago

A boat is pulled toward a dock by means of a rope wound on a drum that is located 6 ft above the bow of the boat. If the rope is

Monica [59]

Answer:

Step-by-step explanation:

Given that:

The height of the dock (h) = 6

Let represent d to be the distance between the boat and the dock

Let the length of the rope between the boat and the drum be denoted by (l)

Then, the rate of change for the length of the rope be:

dl/dt = -5 ft/s

Using Pythagoras rule to determine the relationship between these values, we have:

$l^2 = h^2 +d^2$

$l^2 = 6^2 + d^2$

$l^2 = 36 + d^2$

We relate to: $2l * \dfrac{dl}{dt} = 2d* \dfrac{dd}{dt}$

From the question;

l = 34,

So to find $\dfrac{dd}{dt}$ , we get;

$d = \sqrt{l^2 - 36}$

$d = \sqrt{34^2 - 36}$

$d = \sqrt{1156- 36}$

$d = \sqrt{1120}$

d = 33.46

So, we have:

$\dfrac{dd}{dt}= \dfrac{l}{d} \times \dfrac{dl}{dt}$

$\dfrac{dd}{dt}= \dfrac{34}{33.46} \times - 5$

$\dfrac{dd}{dt}= 1.016 \times - 5$

$\dfrac{dd}{dt}=-5.08 \ ft/sec$

4 0

3 years ago