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NNADVOKAT [17]
3 years ago
15

Solve the system of equations. 6x+3y=9 2x+3y=1

Mathematics
1 answer:
Volgvan3 years ago
3 0
X+3y=9%6
X+y=3%3=1thats it please solve another one in same way
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Simplify 10 – 3x – 13 + 5x<br><br> A. 2x – 3<br><br> B. 1<br><br> C. 3 – 3x<br><br> D. 3 – 2x
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7 0
3 years ago
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Josie hikes at 2 and 3/4 miles per hour. How long will it take her to hike 9 and 5/8 miles?
Leviafan [203]
First, let's convert the givens to decimals to make calculations easier:
2 (3/4) = 2.75
9(5/8) = 9.625

We are given that:
Josie can hike 2.75 miles in one hour.
To know the time that Josie would take to hike 9.625 miles, we will simply do cross multiplication as follows:
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6 0
3 years ago
An integer N is to be selected at random from {1, 2, ... , (10)3 } in the sense that each integer has the same probability of be
Andrej [43]

Answer:

Probability of N Divisible by 3 - 0.33

Probability of N Divisible by 5 - 0.2

Probability of N Divisible by 7 - 0.413

Probability of N Divisible by 15 - 0.066

Probability of N Divisible by 105 - 0.0095

Step-by-step explanation:

Given data:

Integer N {1,2,.....10^3}

Thus total number of ways by which 1000 is divisible by 3 i.e. 1000/3 = 333.3

Probability of N divisible by 3 {N%3 = 0 } = \frac{333.3}{1000} = 0.33

total number of ways by which 1000 is divisible by 5 i.e. 1000/5 = 200

Probability of N divisible by 5 {N%5 = 0 } = \frac{200}{1000} = 0.2

total number of ways by which 1000 is divisible by 7 i.e. 1000/7 = 142.857

Probability of N divisible by 7 {N%7 = 0 } = \frac{142.857}{1000} = 0.413

total number of ways by which 1000 is divisible by 15 i.e. 1000/15 = 66.667

Probability of N divisible by 15 {N%15 = 0 } = \frac{66.667}{1000} = 0.066

total number of ways by which 1000 is divisible by 105 i.e. 1000/105 = 9.52

Probability of N divisible by 105 {N%105 = 0 } = \frac{9.52}{1000} = 0.0095

similarly for N is selected from 1,2.....(10)^k where K is  large then the N value. Therefore effect of k will remain same as previous part.

3 0
3 years ago
Read 2 more answers
The number of males in the classroom is three more than twice the number of females. Of the total number of students is 57, how
dolphi86 [110]

Answer:

Step-by-step explanation:

Given that the number of males in the classroom is three more than twice the number of females.

the total number of students is 57

Let x be the no of males then no of females = 57-x

Also we have 3 more than twice no of females as

2(57-x)+3

This equals x

2(57-x)+3=x\\114-2x+3=x\\3x=117\\x=39

No of males = 39, no of females = 18

6 0
3 years ago
Solve the equation. Check your solutions when necessary.<br><br><br>2x² − 7x = 4
prisoha [69]

Answer:

x= -1/2 = -0.500

x=4

Step-by-step explanation:

2x^2-7x-4=0

2x^2-8x+1x-4=0

2x(x-4)+1(x-4)=0

(2x+1)(x-4)=0

2x+1=0...2x= -1.. x= -1/2         x-4=0 .. x=4

checking the solution

2(-1/2)^2-7(-1/2)=4.....  4=4

2(4)^2-7(4)=4....... 4=4

5 0
2 years ago
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