Solve the system of equations. 6x+3y=9 2x+3y=1

What is the monthly payment for a $20,230 loan at 11.5 percent for 20 years?

yKpoI14uk [10]

The main formula is
M= P (i(1+i)^n) / (1+i)^n) - 1
M: monthly payment
P: mortgage principale= $20,230
i=montly interest, 11.5%=11.5/100=0.115, i= 0.115/12=0.009
n=number of months=12x20(years)=240 months

M= $20,230(0.009(1.009)^240) / (1.009)^240-1=$20,230 x 0.0077 / 8.58-1
M=$20.57

4 0

3 years ago

Suppose that your mom gives you $20 to go to the school supplies store. there is a 6% sales tax on supplies. you need to buy the

sasho [114]

The answers are -
a - $13.90
b - $6.10

4 0

2 years ago

4. Identify the zeros and the graph of the function y = x(x − 2)(x + 5).

Natalka [10]

The zeros of

y = x(x + 2)(x + 5)y=x(x+2)(x+5)

are

x=0,x=-2,x=-5x=0,x=−2,x=−5

EXPLANATION

The given function is

y = x(x + 2)(x + 5)y=x(x+2)(x+5)

To find the zeros of the above function, we just have to equate the function to zero and solve for x.

x(x + 2)(x + 5) = 0x(x+2)(x+5)=0

This implies that,

x = 0 \: \: or \: x + 2 = 0 \:or \: x + 5 = 0x=0orx+2=0orx+5=0

x = 0 \: \: or \: x = - 2\:or \: x = - 5x=0orx=−2orx=−5

To graph the above function, we need to consider the multiplicity.

We can see that the multiplicity of the roots are odd. This means that, the graph crosses the x-axis at each x-intercept.

We also need to consider the position of the graph on the following intervals,

x < - 5x<−5

When

x = - 10x=−10

y = - 10( - 8)( - 5) \: < \: 0y=−10(−8)(−5)<0

The graph is below the x-axis.

- 5 \: < \: x \: < \: - 2−5<x<−2

When

x = - 3x=−3

y = - 3(2)( - 1) \: > 0y=−3(2)(−1)>0

The graph is above the x-axis.

- 2 \: < \: x < \: 0−2<x<0

when

x = - 1x=−1

y = -1(1)(4) \: < \: 0y=−1(1)(4)<0

The graph is below the x-axis.

Finally the interval,

x \: > \: 0x>0

when

x = 1x=1

y = 1(3)(6) \: > \: 0y=1(3)(6)>0

The graph is above the x-axis.

We can now use the above information to sketch graph as shown in the diagram above

3 0

2 years ago

Graph a line with a slope of 1/4 that contains the point (6, 3).

Semenov [28]

Answer:

The graph in the attached figure

Step-by-step explanation:

we know that

The equation of a line in point slope form is

$y-y1=m(x-x1)$

we have

$(x_1,y_1)=(6,3)$

$m=\frac{1}{4}$

substitute

$y-3=\frac{1}{4}(x-6)$

The easiest way to graph a line is to calculate the intercepts

The x-intercept is the value of x when the value of y is equal to zero

For y=0

$0-3=\frac{1}{4}(x-6)$

$-12=(x-6)$

$x=-12+6=-6$

The x-intercept is the point (-6,0)

The y-intercept is the value of y when the value of x is equal to zero

For x=0

$y-3=\frac{1}{4}(0-6)$

$y-3=-\frac{3}{2}$

$y=-\frac{3}{2}+3$

$y=1.5$

The y-intercept is the point (0,1.5)

Plot the intercepts and join the points to graph the line

(-6,0) and (0,1.5)

The graph in the attached figure

8 0

2 years ago

I need you help, help me pleaseeeee

mrs_skeptik [129]

Answer:

y=4x+2 is answer .......

4 0

3 years ago

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