Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
Answer:
he made the mistake on step one, he didn't distribute correctly
Step-by-step explanation:
-5(x-1) = -5x +5
not -5x - 1
Answer:
The answer is A -60
Step-by-step explanation:
u soppost to multiply 5×-12
The lamp is about 90 cm. to get this answer you take 36 and multiply it by 2.5.
Total number of cards = 25 .
Total number of possible draws = 25
Number of possible successes = 5
(The successful draws are 1, 2, 3, 9, and 18.)
Probability of success = 5/25 = <em>1/5 </em> = 0.2 = 20%