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2 years ago

What is the area of this triangle??

Mathematics

1 answer:

dezoksy [38]2 years ago

6 0

Answer:

248

Step-by-step explanation:

A=height b times base divided by two

which is:

A= 16 times 31 divided by two

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The figure shows the dimensions of the side panel of a skateboard ramp what is the area of this panel.

Flauer [41]

28.7 is the answer to your question.

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4 years ago

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PLEASE HELP ME!!! WHOEVER CAN!!

Alex787 [66]

Answer:

deltamath right? lol understand

Step-by-step explanation:

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4 years ago

Surya is competing in a triathlon that includes swimming, bicycling and running. For the first two segments of the race, Surya s

kirill115 [55]

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3 years ago

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At Furnace Woods School, enrollment increased from 320 students in 2006 to 349 students in 2007. What is the percent increase in

drek231 [11]

Answer:

9.0625%

Step-by-step explanation:

It increased from 320 to 349

This is a percent INCREASE.

320 is the "old" value and 349 is the "new" value.

We find percent increase by the formula:

$\frac{New-Old}{Old}*100$

Where old is 320 and new is 349. Lets substitute and find the increase (percentage):

$\frac{New-Old}{Old}*100\\=\frac{349-320}{320}*100\\=\frac{29}{320}*100\\=9.0625$

The percentage increase is 9.0625%

5 0

3 years ago

Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,

$undefined$

4 0

1 year ago