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rodikova [14]
3 years ago
11

A buyer owes a supplier $820. The terms were 3/10, n/60. Within 10 days, the buyer sent in a payment of $140. How much is the ne

w balance? (Round your answers to the nearest hundredth)
Mathematics
1 answer:
Margaret [11]3 years ago
7 0

Answer:

The new balance is $675.8

Step-by-step explanation:

Solution

Given that

The total amount of loan = $820.

The terms were = 3/10, n/60

Within 10 days, the buyer sent in a payment of  =$140

What is the new balance =?

Now,

3/10 =  if the amount is paid in 10 days, a discount of is included

n/60 = This means that all amount should be paid within 60 days

Thus,

$140 for 3/10 as this is paid within 10 days

140 *3% = 140 * 3/100

we get

=$4.2 of discount

Then,

The balance amount becomes $ 820 - 140 -4.2

=$675.8

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ANSWER
{a}^{3}  + {b}^{3} = (a + b)( {a}^{2 }  - ab +  {b}^{2} )


EXPLANATION

To find the expression that is equivalent to
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So let's get started.


{(a + b)}^{3}  = (a + b) {(a + b)}^{2}

We expand the parenthesis on the right hand side to get,



{(a + b)}^{3}  = (a + b) ( {a}^{2} + 2ab +  {b}^{2}  )



We expand again to obtain,

{(a + b)}^{3}  =  {a}^{3}  + 3 {a}^{2}b + 3a {b}^{2}   +  {b}^{3}


Let us group the cubed terms on the right hand side to get,

{(a + b)}^{3}  =  {a}^{3}   +  {b}^{3}  + 3 {a}^{2}b + 3a {b}^{2}




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We make the cubed terms the subject,

{(a + b)}^{3}  - 3ab (a+ b) =  {a}^{3}   +  {b}^{3}

We factor to get,


(a + b)({(a + b)}^{2}  - 3ab ) =  {a}^{3}   +  {b}^{3}


We expand the bracket on the left hand side to get,

(a + b)( {a}^{2}  + 2ab +  {b}^{2}   - 3ab ) =  {a}^{3}   +  {b}^{3}


We finally simplify to get,

(a + b)( {a}^{2}   - ab +  {b}^{2}  ) =  {a}^{3}   +  {b}^{3}
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