To evaluate this expression properly, we must follow order of operations (PEMDAS) rules. Here, that means doing exponentiation first, followed by mult. and div., followed by addition and subtraction.

2−4÷2+2^3 becomes 2−4÷2+8 after exponentiation.

2−4÷2+8 becomes 2-2+8 after division.

2-2+8 = 8

Your final value for this expression is 8.

4 0

3 years ago

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In △ABC, point P∈ AB is so that AP:BP=1:3 and point M is the midpoint of segment CP . Find the area of △ABC if the area of △BMP

matrenka [14]

Answer: Area of ΔABC = 56m².

Explanation:

Since we have given that

point P∈ AB, such that AP:BP=1:3

Point M is the midpoint of segment CP.

Now, we have given that

Area of ΔBMP=21 m²

Since M is the mid-point of CP, so,

Area of ΔCMP= 21 m².

So, Area of ΔBCP = 21+21=42 m²

According to question,

$\frac{3}{4}\times x= 42\\\\x=\frac{42}{3}=14\\\\\text{ Area of }\triangle APC=14m^2\\\\$

So, area of ΔABC is given by

$42+14=56m^2$

Hence, area of ΔABC =56m².

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4 years ago

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Which point is on the graph of a direct variation equation in which k = 1.8? A. (4, 0.45) B. (7.2, 4) C. (4, 7.2) D. (0.45, 4)

icang [17]

The answer is B (7.2, 4).

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4 years ago

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