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3 years ago

What is the axis of symmetry of y=x2–4x—8

Mathematics

2 answers:

miv72 [106K]3 years ago

6 0

The answer is 2 I think

grandymaker [24]3 years ago

4 0

X=2 it is the axis of symmetry.

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If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf

jonny [76]

With the curve $C$ parameterized by

$C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k$

with $0\le t\le\dfrac\pi2$ , and given the vector field

$\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k$

the work done by $\mathbf f$ on a particle moving on along $C$ is given by the line integral

$\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt$

where

$\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt$

The integral is then

$\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt$
$=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t$
$=269$

6 0

3 years ago

2(3 – 4a) + 5(a – 7) what are the steps to solve this? please.

Doss [256]

2(3-4a) + 5(a-7) first do the distributive property
6-8a + 5a-35 now combine like terms
-41 - 3a is the final answer

7 0

3 years ago

Read 2 more answers

If x can be any integer what is the greatest possible value of 1^x - |x|

natali 33 [55]

x=1
Is dat what u want? If not tell me and I'll help u

Hope this helped :)

4 0

2 years ago

8.01 + 24.192 need answer please

SOVA2 [1]

Answer: 32.202

or 32.20

or 32.2

4 0

2 years ago

Read 2 more answers

T > L+D/B solve for d

damaskus [11]

T>L+D/B
(Assume no parentheses missing and use PEMDAS rule)
Subtract L from both sides
T-L > L-L + D/B
T-L>D/B
Multiply both sides by B (assuming B>0)
B(T-L)>D/B*B
B(T-L)>D
Interchange two sides,
D<B(T-L) (if B>0)
if B<0, then D>B(T-L)

8 0

3 years ago