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aleksklad [387]
3 years ago
15

Can you pls put in order I need help ASAP :3 thanks if you can. I will make Brainly

Mathematics
1 answer:
Brums [2.3K]3 years ago
7 0

Answer:

This might get confusing but bear with me.

The top two are correct, leave them where they are. The 6th one down is step three, the 8th one down is step four, the 3rd one down is step five, the 4th one down is step six, the 7th ne down is step seven so leave it alone, and the 5th one down is step 8.

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In ΔWXY, if m∠W is five less than three times m∠Y and m∠X is 8 more than m∠W, find the measures of each angles?
yulyashka [42]

Answer:

∡W = 73°

∡X = 81°

∡Y = 26°

Step-by-step explanation:

let 'y' = measure angle Y

let '3y - 5' = measure of angle W

let '3y + 3' = measure of angle X

add all together and set equal to 180

y + 3y + 3y - 2 = 180

7y = 182

y = 26

substitute 26 for y in '3y+3' to find measure of angle X

substitute 26 for y in '3y-5' to find measure of angle W

5 0
3 years ago
Can you please help with this.
nlexa [21]
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7 0
3 years ago
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All the numbers that round to 80
Greeley [361]
75,76,77,78,79,80,81,82,83,84

5 0
3 years ago
Evaluate the six trigonometric functions of the angle 0<br><br><br><br>is right<br>​
antiseptic1488 [7]

Answer:

1. Sine θ = 1/3

2. Cos θ = 2√2 / 3

3. Tan θ = √2 / 4

4. Cosec θ = 3

5. Sec θ = 3√2 / 4

6. Cot θ = 2√2

Step-by-step explanation:

We'll begin by determining the adjacent. This can be obtained as follow:

Hypothenus (Hypo) = 9

Opposite (Opp) = 3

Adjacent (Adj) =?

Hypo² = Adj² + Opp²

9² = Adj² + 3²

81 = Adj² + 9

81 – 9 = Adj²

72 = Adj²

Take the square root of both side

Adj = √72

Adj = 6√2

Finally, we shall determine six trigonometric functions of the angle θ. This Can be obtained as follow:

1. Determination of Sine θ

Hypothenus = 9

Opposite = 3

Sine θ =?

Sine θ = Opposite / Hypothenus

Sine θ = 3/9

Sine θ = 1/3

2. Determination of Cos θ

Adjacent = 6√2

Hypothenus = 9

Cos θ =?

Cos θ = Adjacent / Hypothenus

Cos θ = 6√2 / 9

Cos θ = 2√2 / 3

3. Determination of Tan θ

Opposite = 3

Adjacent = 6√2

Tan θ =?

Tan θ = Opposite / Adjacent

Tan θ = 3 / 6√2

Tan θ = 1 / 2√2

Rationalise

(1 / 2√2) × (2√2 /2√2)

= 2√2 / 4×2

Tan θ = √2 / 4

4. Determination of Cosec θ

Sine θ = 1/3

Cosec θ =?

Cosec θ = 1 / Sine θ

Cosec θ = 1 ÷ 1/3

Cosec θ = 1 × 3/1

Cosec θ = 3

5. Determination of sec θ

Cos θ = 2√2 / 3

Sec θ =?

Sec θ = 1 / Cos θ

Sec θ = 1 ÷ 2√2 / 3

Sec θ = 1 × 3 / 2√2

Sec θ = 3 / 2√2

Rationalise

= (3 / 2√2) × (2√2 / 2√2)

= 3 × 2√2 / 4×2

Sec θ = 3√2 / 4

6. Determination of Cot θ

Tan θ = √2 / 4

Cot θ =?

Cot θ = 1 / Tan θ

Cot θ = 1 ÷ √2 / 4

Cot θ = 1 × 4 / √2

Cot θ = 4 / √2

Rationalise

= (4 / √2) × (√2 / √2)

= 4√2 / 2

Cot θ = 2√2

8 0
3 years ago
X-1 divided by x^3+3x^2+3x+2
solmaris [256]

Answer:

76x

Step-by-step explanation:

qdqdqd

8 0
3 years ago
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