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3 years ago

HELP ASAP PLZ

Mathematics

2 answers:

blagie [28]3 years ago

4 0

9/38 x 9 /38 =81/144 both of the events are indepent

Alisiya [41]3 years ago

4 0

Answer:

The correct option is D. 9/38x9/38 =81/1444

Step-by-step explanation:

Total number of marbles in the bag = 38

Number of white marbles in the bag = 14

Number of gray marbles in the bag = 9

Number of blue marbles in the bag = 15

We need to find the probability that Jane takes out a gray marble in both draws

$\text{Probability that Jane draws gray marble in first draw = }\frac{9}{38}$

Given that : Then Jane replaces the marble for the second draw

$\text{Probability that Jane draws gray marble in second draw = }\frac{9}{38}$

$\text{Probability that Jane draws gray marble in both draws = }\frac{9}{38}\times \frac{9}{38}$

$\text{Probability that Jane draws gray marble in both draws = }\frac{81}{1444}$

Therefore, The correct option is D. 9/38x9/38 =81/1444

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Answer:

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2 years ago

If y= 6 when x= 24, find the value of x when y= 7

Shtirlitz [24]

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Step-by-step explanation:

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3 0

3 years ago

Read 2 more answers

The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly

Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between $\\ (\mu - 6\sigma)$ and $\\ (\mu + 6\sigma)$ . It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

$\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027$

For those with defects operating at a 6 sigma level, the probability is:

$\\ 1 - p = 1 - 0.999999998027 = 0.000000001973$

Similarly, for finding no defects in a 5 sigma level, we have:

$\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697$ .

The probability of defects is:

$\\ 1 - p = 1 - 0.999999426697 = 0.000000573303$

Well, the defects present in a six sigma level and a five sigma level are, respectively:

$\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}$

$\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}$

Then, comparing both fractions, we can confirm that a 6 sigma level is markedly different when it comes to the number of defects present:

$\\ {6\sigma} \approx \frac{2}{10^9}$ [1]

$\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9}$ [2]

Comparing [1] and [2], a six sigma process has 2 defects per billion opportunities, whereas a five sigma process has 600 defects per billion opportunities.

8 0

3 years ago

Olivia wants to cut 3 3/4 inches from a piece of string.She has already cut off 2 9/16 inches from the piece of string.How much

Roman55 [17]

Answer: she still has to cut off 19/16 inches.

Step-by-step explanation:

Olivia wants to cut 3 3/4 inches from a piece of string. Converting 3 3/4 inches to improper fraction, it becomes 15/4 inches.

She has already cut off 2 9/16 inches from the piece of string. Converting 2 9/16 inches to improper fraction, it becomes 41/16 inches.

Therefore, the length of string that is left for her to cut off would be

15/4 - 41/16 = (60 - 41)/16

= 19/16 inches

6 0

3 years ago