Answer:
both of the questions are examples of convenience samples
Step-by-step explanation:
A voluntary response would be where the people get to choose to respond to the survey. In both of these cases, teachers are specifically asking for their students opinions.
The requirement is that every element in the domain must be connected to one - and one only - element in the codomain.
A classic visualization consists of two sets, filled with dots. Each dot in the domain must be the start of an arrow, pointing to a dot in the codomain.
So, the two things can't can't happen is that you don't have any arrow starting from a point in the domain, i.e. the function is not defined for that element, or that multiple arrows start from the same points.
But as long as an arrow start from each element in the domain, you have a function. It may happen that two different arrow point to the same element in the codomain - that's ok, the relation is still a function, but it's not injective; or it can happen that some points in the codomain aren't pointed by any arrow - you still have a function, except it's not surjective.
Answer:
28
Step-by-step explanation:
cause
Answer:
Step-by-step explanation:
<u>Linear Combination Of Vectors
</u>
One vector 
is a linear combination of 
and 
if there are two scalars 
such as
In our case, all the vectors are given in 
but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.
We have
We set the equation
Multiplying both scalars by the vectors
Equating each coordinate, we get
Adding the first and the third equations:
Replacing in the first equation
We must test if those values make the second equation become an identity
The second equation complies with the values of 
and 
, so the solution is
Answer:
(-3,0) = x and (0,4) = y
Step-by-step explanation:
