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HACTEHA [7]
3 years ago
14

Peter walked 10m from X to Y on bearing 020° and then he turned and walked 20m to Z with bearing 140° of Z from Y. Find the dist

ance between X and Z. Find the bearing of Z from X.

Mathematics
1 answer:
seraphim [82]3 years ago
3 0

Answer:

17.32m ; 110°

Step-by-step explanation:

Distance between X and Z

To calculate the distance between X and Z

y^2 = x^2 + z^2 - (2xz)*cosY

x = 20, Z = 10

y^2 = 20^2 + 10^2 - (2*20*10)* cos60°

y^2 = 400 + 100 - (400)* 0.5

y^2 = 500 - 200

y^2 = 300

y = sqrt(300)

y = 17.32m

Bearing of Z from X:

Using cosine rule :

Cos X = (y^2 + z^2 - x^2) / 2yz

Cos X = (300 + 100 - 400) / (2 * 20 '*10)

Cos X = 0 / 400

Cos X = 0

X = cos^-1 (0)

X = 90°

Bearing of Z from X

= 20° + X

= 20° + 90°

= 110°

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Find the value of x<br> x° <br> 66°<br> 117°
pogonyaev

Answer:

x = 51 degrees

Step-by-step explanation:

Keep in mind, the angles of a triangle add up to 180 degrees.

A flat line also equals 180 degrees.

First, we should find the lower left angle. We know that 117 plus that angle is going to be 180, since it's a flat line.

180 - 117 = 63

Now, we just need to find angle x. (All 3 of our angles should add up to 180, knowing this, we can put it in an equation)

63 + 66 + x = 180

Then, you solve for x:

(63+66) + x = 180

129       + x = 180

-129             -129

               x = 51

Hope this helps :)

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