Why do whole numbers raised to an exponent get greater well fractions raised to an exponent get smaller

1 answer:

4 0

Because when you raise an exponent on a fraction, it is basically dividing into itself. Imagine 1/3 multiplied my 3 (Ans is 1), the fractions aren't whole numbers so when they multiply into another number, it uses division

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Last Friday Stefan had $35. Over the weekend, his parents gave him some money for

Usimov [2.4K]

Answer:

35+x=47

Step-by-step explanation:

let x be the money that his parents give him for washing the car.

8 0

3 years ago

How many different 1, 2, or 3 digit whole numbers can be made using the digits 2,5, and 8? No digit may be repeated within 1 num

dezoksy [38]

With one digit you can only make three numbers, 2, 5, and 8.
With two digits, _ _ there are 3 possibilities for the first digit and 2 in the second totaling 3*2 = 6 possibilities.
With three digits, _ _ _, there are 3 possibles in the first digit, 2 in the second and only 1 in the last. 3*2*1 = 6
Now we add all of the possibilities - 3+6+6 = 15.

Your final answer should be 15 numbers. Hope this helps!

6 0

4 years ago

Can someone help me in this plssss I really need it

kompoz [17]

Answer:

$\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}$

Step-by-step explanation:

Your expression is

$\sqrt [3] {-54x^{5}y^{6}}$

Here's how I would simplify it.

$\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}$

$\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}$