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Leokris [45]
3 years ago
14

A window is 12 feet above the ground. A ladder is placed on the ground to reach the window. If the bottom of the ladder is place

d 5 feet away from the building, what is the length of the ladder?
Mathematics
2 answers:
murzikaleks [220]3 years ago
8 0
You will need to use Pythagorean theorem a^2 + b^2 = c^2
the a and b values will be 12 and 5 feet. So just plug them in and solve for c.
12^2 + 5^2 = c^2
144 + 25 = c^2
169 = c^2 square root both sides
13 = c
so the ladder has a length of 13 feet.
Oksanka [162]3 years ago
5 0

Answer:

The answer would be 17 or 6 square root 8

Step-by-step explanation:

This is a question that cant be solved by Pythagorean theorem

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Tom spent 153 minutes completing a race. He walked 63 minutes and jogged the rest. What is the ratio of time he jogged to time h
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Subtract 153-63=90 and I am pretty sure that's what you have to do
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What is greater 95 percent or 0.9
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Nick's dad wanted to measure the length of his backyard and asked Nick to do this with his footsteps. Since it was winter, they
Lerok [7]

Answer:

2244 cm

Step-by-step explanation:

The first first thing we must do is find the LCM of the following numbers

(51; 68) = 204.

This means that the first time they coincide is at 204.

Now, since his steps always coincide after 204

In Nick's case

Nick's 204 ÷ 51 = 4th step

and in the case of the father

204 ÷ 68 of his father = 3rd step.

Which means that in the 204 cm distance, there will be a total of 6 foot steps, except in the first 204 cm when your "initial" step is counted.

Replacing these values we have that the total distance will be:

67-1 (initial step) / (6 * 204) = 2244 cm

7 0
3 years ago
Express 16 as a difference of two prime numbers
sasho [114]
16 can be expressed as a difference of two prime numbers in two ways, which is:23 - 7 = 16, 19 - 3 = 16
Among the choices, 16 is expressed as (23 - 7), which is the difference of two prime numbers.

8 0
3 years ago
A sample of 11001100 computer chips revealed that 62b% of the chips fail in the first 10001000 hours of their use. The company's
STALIN [3.7K]

Answer:

Rule

If;

P-value > significance level --- accept Null hypothesis

P-value < significance level --- reject Null hypothesis

Z score > Z(at 90% confidence interval) ---- reject Null hypothesis

Z score < Z(at 90% confidence interval) ------ accept Null hypothesis

Null hypothesis: H0 = 0.60

Alternative hypothesis: Ha <> 0.62

z score = 1.35

P value = P(Z<-1.35) + P(Z>1.35) = 0.0885 + 0.0885= 0.177

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = 1.35) falls with the region bounded by Z at 0.1 significance level. And also the two-tailed hypothesis P-value is 0.177 which is greater than 0.1. Then we can conclude that we don't have enough evidence to FAIL or reject the null hypothesis, and we can say that at 0.10 significance level the null hypothesis is valid.

Question; A sample of 1100 computer chips revealed that 62% of the chips fail in the first 1000 hours of their use. The company's promotional literature states that 60% of the chips fail in the first 1000 hours of their use. The quality control manager wants to test the claim that the actual percentage that fail is different from the stated percentage. Determine the decision rule for rejecting the null hypothesis, H0, at the 0.10 level.

Step-by-step explanation:

Given;

n=1100 represent the random sample taken

Null hypothesis: H0 = 0.60

Alternative hypothesis: Ha <> 0.62

Test statistic z score can be calculated with the formula below;

z = (p^−po)/√{po(1−po)/n}

Where,

z= Test statistics

n = Sample size = 1100

po = Null hypothesized value = 0.60

p^ = Observed proportion = 0.62

Substituting the values we have

z = (0.62-0.60)/√{0.60(1-0.60)/1100}

z = 1.354

z = 1.35

To determine the p value (test statistic) at 0.01 significance level, using a two tailed hypothesis.

P value = P(Z<-1.35) + P(Z>1.35) = 0.0885 + 0.0885= 0.177

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = 1.35) falls with the region bounded by Z at 0.1 significance level. And also the two-tailed hypothesis P-value is 0.177 which is greater than 0.1. Then we can conclude that we don't have enough evidence to FAIL or reject the null hypothesis, and we can say that at 0.10 significance level the null hypothesis is valid.

3 0
3 years ago
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