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natali 33 [55]
3 years ago
9

A can of juice has a radius of 4 inches and height of 7 inches . what is the volume of can ?​

Mathematics
1 answer:
finlep [7]3 years ago
5 0
Habana baja zkGuabjavavav
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If NO = 17 and NP = 5x -6, find the value of x. Then find NO and OP.
yan [13]
Well lets assume that NO = NP. If this is the case then 17 = 5x - 6. We then want to solve for x. So add 6 to each side, this equals 23 = 5x. I do not know if it is suppose to be a decimal, but I will do it anyway. Divide 23 by 5 which is 4.6. So x = 4.6. Now plug this into x. So NO = 17 and NP = 17. This is the only way I see possible to solve this problem. Let me know if it was correct please.
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Translate to an algebraic expression the sum of D and F is
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D+F=N: n is the variable (the sum).
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A function of the form f(x) ott is modified so that the b value remains the same but the a value is increased by 2. How do
Digiron [165]

Answer:

Step-by-step explanation:

.

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MrRissso [65]
I hope this helps you

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An engineer wishes to determine the width of a particular electronic component. If she knows that the standard deviation is 1.6
nexus9112 [7]

Answer:

n=1705

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma=1.6)  

And the distribution for \bar X is:

\bar X \sim N(\mu, \frac{1.6}{\sqrt{n}})  

We know that the margin of error for a confidence interval is given by:  

Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)  

The next step would be find the value of \z_{\alpha/2}, \alpha=1-0.99=0.01 and \alpha/2=0.005  

Using the normal standard table, excel or a calculator we see that:  

z_{\alpha/2}=\pm 2.58  

If we solve for n from formula (1) we got:  

\sqrt{n}=\frac{z_{\alpha/2} \sigma}{Me}  

n=(\frac{z_{\alpha/2} \sigma}{Me})^2  

And we have everything to replace into the formula:  

n=(\frac{2.58(1.6)}{0.1})^2 =1704.03  

And if we round up the answer we see that the value of n to ensure the margin of error required \pm=0.1 mm is n=1705.  

6 0
2 years ago
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