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abruzzese [7]
3 years ago
11

Pls help me with this​

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
5 0

Answer:

\boxed{\sf \frac{15}{22} }

Step-by-step explanation:

The radius of the circle is 7 cm.

The two legs of the triangles are 7cm as well.

Area of a trinagle is ( base × height )/2.

\frac{7 \times 7}{2} =24.5

Multiply the value by 2 since there are two triangles.

24.5 \times 2 = 49

Calculate the area of the circle.

\pi r^2

The radius is given.

\pi (7)^2

Take \pi as \frac{22}{7}

49(\frac{22}{7} )

=154

Subtract the area of the two triangles from the area of the whole circle.

154-49=105

The area of the shaded part is 105 cm². The total area of the shape is 154cm².

\frac{105}{154} =\frac{15}{22}

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PLEASE LED ME THE ANSWER<br> ILL GIVE YOU 20 POINTS
krok68 [10]

Answer:

DEC+DEF=180

DEC=180-116

DEC=64°

in triangle DCE

angle D+angle C+angle E=180

7y+6+4y+64=180

11y+70=180

11y=180-70

11y=110

y=110/11

y=10°

angle C=4y

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3 0
3 years ago
A cylinder has a height of 12 feet and a radius of 5 feet. What is its volume? Use ​ ≈ 3.14 and round your answer to the nearest
beks73 [17]

Answer: The volume is 942 cubic feet   , 942 ft^3

Step-by-step explanation:

The formula for the volume of a cylinder is  v = pi* r^2 * h

Where v is the volume, r is the radius and h is the height.

Input the values for pi, radius, and the height into the formula to solve for the volume.

v = 3.14* (5^2) * 12

V = 3.14* 25 * 12

V = 942

7 0
3 years ago
Someone help. (Find the area of a rectangle with a lenght of 5a^2 b^4 and a width of (3ab^3)^2
Dmitry_Shevchenko [17]

Answer:

All you do is just multiply them.

Step-by-step explanation:

5a^2 b^4(3ab^3)^2=

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3 0
3 years ago
SOMEONE.HALP.ME.
Natasha2012 [34]
3/4 = 0.75 in decimal inch
Karla wants to leave 0.75 inch in her signature.
4 -0.75 = 3.25 inch needed
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3 and 1/4 inches is needed.
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3 years ago
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zysi [14]

Answer:

7.5 MW

Step-by-step explanation:

The power generated from a falling water is a function of its height and volume. The power generated an be calculated using the formula:

Power (P) = Density(ρ) * volume flow rate(Q) * acceleration due to gravity(g) * height(h)

P = ρQgh

But Qh = Velocity(v) * volume(V).

Hence power = ρvgV

Given that ρ of water = 1000 kg/m³, v = 75 m/s, V = 10 m³, g = 10 m/s². Substituting:

P = ρvgV = 1000 * 75 * 10 * 10 = 7500000 W

P = 7.5 MW

4 0
3 years ago
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