1/3
Hope this helps! :)
(I’m actually doing IXL too lol)
Answer:
-4, 3 1/2 JFURE8EGNRODG RE NEJEUSUEHEUE I did this for 20 characters
I'm assuming that the diagonals intersect at E. Since diagonals of a parallelogram bisect each other, BE=ED.
- 7x-2=x²-10
- x²-7x-8=0
- (x-8)(x+1)=0
- x = -1, 8
As distance must be positive, we reject the negative case, so x=8.
Thus, BE=ED=54.
Answer:
Step-by-step explanation:
1a+1b(a+b-c)+1b+1c(b=c-a)+ 1a+1c(c+a-b)
1a+1b-c+1b +1c-a+1a+1c-b
1a+2b-c+a+1c-b
2a+1b+c this is the answer I think lol
Two consecutive odd integers have a difference of 2. If you let the smaller one of them be x, the other one is x + 2.
Their sum is -36, so add x and x + 2, and set equal to -36. Then solve for x to find the smaller one. Finally, 2 more than x is the greater of the two integers.
x + x + 2 = -36
2x + 2 = -36
2x = -38
x = -19
The smaller one of the two integers is -19.
x + 2 = -19 + 2 = -17
The greater of the two integers is -17.
Answer: The integers are -19 and -17.
