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Novay_Z [31]
3 years ago
11

A set of barstools were priced $284.80 after a 20% discount was applied. What was the price of the set of barstools before the d

iscount?
Mathematics
1 answer:
Lorico [155]3 years ago
5 0

Answer:

  $356.00

Step-by-step explanation:

If d represents the discounted price, and p is the original price, you have ...

  d = p - 20% × p = p(1 -20%) = 0.80p

Then the original price is ...

  p = d/0.80 . . . . . divide by the coefficient of p

  p = $284.80/0.80 = $356.00

The price before the discount was $356.00.

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What is the probability that a student who bought juice chosen at random purchased grape flavor
larisa [96]

Answer:

50% chance

Step-by-step explanation:

6 0
3 years ago
11+8q=3q-19 I need help please idk the answer
iren2701 [21]

Answer:

-6

Step-by-step explanation:

1) combine all like terms

(bring 3q to the left and 11 to the right so you can combine the like terms)

(doing that will make 3q negative and 11 negative since your moving them so their sign changes as well)

8q-3q=-19-11

5q=-30

Q=-6

Hope this helps

4 0
3 years ago
What is 2+(9-5)x7-3/4
Cloud [144]
I got 9.75 hope it's right
5 0
3 years ago
A distance AB is observed repeatedly using the same equipment and procedures, and the results, in meters, are listed below: 67.4
skad [1K]

Answer:

a) \bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401

b) The sample deviation is calculated from the following formula:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And for this case after replace the values and with the sample mean already calculated we got:

s=0.0036

If we assume that the data represent a population then the standard deviation would be given by:

\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}

And then the deviation would be:

\sigma =0.00319

Step-by-step explanation:

For this case we have the following dataset:

67.401, 67.400, 67.402, 67.396, 67.406, 67.401, 67.396, 67.401, 67.405, and 67.404

Part a: Determine the most probable value.

For this case the most probably value would be the sample mean given by this formula:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

And if we replace we got:

\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401

Part b: Determine the standard deviation

The sample deviation is calculated from the following formula:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And for this case after replace the values and with the sample mean already calculated we got:

s=0.0036

If we assume that the data represent a population then the standard deviation would be given by:

\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}

And then the deviation would be:

\sigma =0.00319

3 0
4 years ago
Helppppp
sasho [114]

Answer:

186.5 + 2x

Step-by-step explanation:

First, radify 25. Luckily it's a perfect square so it will be 5.

Second, divide within the parentheses. You're expression should look like this.

(93-5+x+42/8)2

Divide 42/8. The decimal form would be 5.25, while the fraction should be 5 1/4.

Third, solve within the parentheses from left to right. Right now you're expression should look like this:

(93-5+x+5.25)2

Add all like terms

93-5+5.25=93.25

Fourth, multiply. Right now the expression should look like this:

(93.25 + x) 2

186.5 + 2x

8 0
3 years ago
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