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MaRussiya [10]
3 years ago
14

What is the y-intercept of a line with the equation (y - 3) = 5(x + 2)?

Mathematics
1 answer:
Nookie1986 [14]3 years ago
7 0
The y-intercept would be (0, 13)
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Given: AABC, AC = 5<br> m C = 90°<br> m A= 22°<br> Find: Perimeter of AABC<br> A<br> C<br> B
Leto [7]

9514 1404 393

Answer:

  perimeter ≈ 12.4 units

Step-by-step explanation:

The side adjacent to the angle is given. The relationships useful for the other two sides are ...

  Tan = Opposite/Adjacent

  Cos = Adjacent/Hypotenuse

From these, we have ...

  opposite = 5·tan(22°) ≈ 2.02

  hypotenuse = 5/cos(22°) ≈ 5.39

Then the perimeter is ...

  P = a + b + c = 2.02 + 5 + 5.39 = 12.41

The perimeter of ∆ABC is about 12.4 units.

7 0
3 years ago
Use the diagram to solve for x.
Vanyuwa [196]

Answer:

0

Step-by-step explanation:

Angle x+45  = (145-55) / 2

2x + 90 = 90

2x = 0

x = 0

5 0
2 years ago
How do you use a number line to solve 235+123
Karolina [17]
You draw a number line do +100 on the line then do +100 +100 +50 +8 then you add them up
8 0
3 years ago
Find the area of the shaded region. Round your answer to the nearest tenth. 9 m 20 9 m area aboutm? pls explain how.
Alenkinab [10]

Answer:

The area of the shaded region is 17.4 square meters.

Step-by-step explanation:

Since the shaded region in the center equals the remainders of a circle, the area of a square equals its side squared, and the area of a circle equals π times the radius squared, for To determine the area of the shaded region, the following calculations should be performed:

(9 ^ 2) - (π x (9/2) ^ 2) = X

81 - (π x 4.5 ^ 2) = X

81 - (3.141 x 4.5 ^ 2) = X

81 - 3.141 x 20.25 = X

81 - 63.6 = X

17.4 = X

Thus, the area of the shaded region is 17.4 square meters.

5 0
3 years ago
Kain graphs the hyperbola (y+2)^2/64 − (x+5)^2/36 = 1 . How does he proceed? Drag a value, phrase, equation, or coordinates in t
cupoosta [38]

Answer:

1st box: (-5,-2)

2nd box: up and down

3rd box: 8

4th box: +-4/3

5th box: y+2 = +-4/3 (x+ 5)

Step-by-step explanation:

Just took the k12 unit test, hope this helps!

7 0
3 years ago
Read 2 more answers
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