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Mumz [18]
2 years ago
9

Help!!! 1/3x - 3/4 + 5/6x = -2

Mathematics
1 answer:
Alex73 [517]2 years ago
3 0

Answer:

x=-15/14

Step-by-step explanation:

1/3x+5/6x=-2+3/4

7/6x=-5/4

x=-15/14

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3 years ago
HELP PLEASE! Thanks :)
Alex Ar [27]
Pi. I don't know what the square root is doing there because it has no number under it.
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2 years ago
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Please help me with this!!
bearhunter [10]

Answer:

8.06

Step-by-step explanation:

Use the Pythagorean theorem:

a^{2} +b^{2} =c^{2}

The hypotenuse is always the slanted side, or c (x in this picture), but the other numbers can be interchanged. Doesn't matter.

Plug the numbers 4 and 7 into the formula.

4^{2} +7^{2} =c^{2} \\

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notsponge [240]

Answer:

Option C 7 is your answer ☺️☺️☺️

4 0
3 years ago
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In a certain community, 30% of the families own a dog, and 20% of the families that own a dog also own a cat. It is also known t
Komok [63]

Answer:

What is the probability that a randomly selected family owns a cat? 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%

Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:

Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)

So, 30% of the families own a dog = .30*100 = 30

20% of the families that own a dog also own a cat = 0.2*30 = 6

34% of all the families own a cat = 0.34*100 = 34

Dogs and cats: 6

Only dogs: 30 - 6 = 24

Only cats: 34 - 6 = 28

Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42

What is the probability that a randomly selected family owns a cat?

34/100 = 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?

A = doesn't own a dog

B = owns a cat

P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%

5 0
2 years ago
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