Which of these graphs below represents a function?

Mathematics

1 answer:

Molodets [167]3 years ago

4 0

Answer:

the one you've selected pink, (the one that looks like a U)

Step-by-step explanation:

if you can pass a vertical line through a supposed function and have it only cross once, it's a function.

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Use the unit circle to find sec (-90)

andreyandreev [35.5K]

Using the unit circle, you can visualise the secant as follows:

Draw the vertical line passing trough (1,0)
Extend the radius until it meets this line at point P
The length of OP is the secant of your angle.

Since -90 means that the radius points downwards, it means that the radius is vertical as well, and thus it never meets the vertical line through (1,0).

Thus, the secant is not defined at -90.

In fact, if we switch back to the function notation, we can confirm this claim, since we have

$\sec(x)=\dfrac{1}{\cos(x)}\implies \sec(-90)=\dfrac{1}{\cos(-90)}=\dfrac{1}{0}$

which is undefined.

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3 years ago

Find the distance CA

katrin [286]

C' ( 0, 3)

A' ( 2 , 1)

C'A' = CA

C'A' = √(2^2 + 2^2) = √8 = 2√2

C'A' = CA = 2√2

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3 years ago

If n = 5 and r = 3 Find "Cr.

Marat540 [252]

Answer:

Cr = 10

Step-by-step explanation:

To calculate combinations we use the nCr formula: nCr = n! / r! * (n - r)!, where n = number of items, and r = number of items being chosen at a time.

$C(n,r)=[?]$