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3 years ago

What’s 229 in scientific notation

Mathematics

1 answer:

skad [1K]3 years ago

8 0

2.29 x 10 to the second power

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n 2000 the population of a small village was 2,400. With an annual growth rate of approximately 1.68%, compounded continuously,

Nitella [24]

Answer:

The population would be 3358

Step-by-step explanation:

Since, exponential growth function if the growth is compound continuously,

$A = Pe^{rt}$

Where,

P = initial population,

r = growth rate per period,

t = number of periods,

Given,

The population in 2000, P = 2,400,

Growth rate per year = 1.68% = 0.0168,

Number of years from 2000 to 2020, t = 20,

Thus, the population in 2020,

$A=2400 e^{0.0168\times 20}$

$=2400 e^{0.336}$

$= 3358.4136$

$\approx 3358$

6 0

3 years ago

A survey indicated that 3 out of 5 doctors use brand X aspirin. If 2000 doctors were surveyed, how many used brand X?

Blizzard [7]

2000(3/5)

6000/5

1200

So 1200 doctors used brand X

8 0

3 years ago

ASAP<br><br> (only the answer pls)

atroni [7]

Answer:

B..........................................

3 0

2 years ago

Determine the equations of the vertical and horizontal asymptotes, if any, for g(x)=x-2/x^2+4x+3

KatRina [158]

Answer:

Step-by-step explanation:

$g(x)=\dfrac{x-2}{x^2+4x+3}\\\\vertical\ asymptote:\\\\x^2+4x+3=0\\x^2+x+3x+3=0\\x(x+1)+3(x+1)=0\\(x+1)(x+3)=0\iff x+1=0\ \vee\ x+3=0\\\\\boxed{x=-1\ \vee\ x=-3}\\\\horizontal\ asymptote:\\\\\lim\limits_{x\to\pm\infty}\dfrac{x-2}{x^2+4x+3}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(\frac{1}{x}-\frac{2}{x^2}\right)}{x^2\left(1+\frac{4}{x}+\frac{3}{x^2}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{\frac{1}{x}-\frac{2}{x^2}}{1+\frac{4}{x}+\frac{3}{x^2}}=\dfrac{0}{1}=0\\\\\boxed{y=0}$

4 0

3 years ago

What is the third quartile of {6, 9, 16, 11, 12, 16, 5, 14, 5}

Evgen [1.6K]

12 is the median

Q1 is 12.5

Q3 is 9.5

The answer is 9.5

Hope this helps!

8 0

3 years ago

Read 2 more answers