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Monica [59]
3 years ago
7

What’s 229 in scientific notation

Mathematics
1 answer:
skad [1K]3 years ago
8 0
2.29 x 10 to the second power
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Compare the functions shown below:<br><br> Which function has the greatest maximum y-value?
solmaris [256]
Answer: It's a tie between f(x) and h(x). Both have the same max of y = 3

The highest point shown on the graph of f(x) is at (x,y) = (pi,3). The y value here is y = 3.

For h(x), the max occurs when cosine is at its largest: when cos(x) = 1. 
So,
h(x) = 2*cos(x)+1
turns into
h(x) = 2*1+1
h(x) = 2+1
h(x) = 3
showing that h(x) maxes out at y = 3 as well

--------------------------------

Note: g(x) has all of its y values smaller than 0, so there's no way it can have a max y value larger than y = 3. See the attached image to see what this graph would look like if you plotted the 7 points. A parabola seems to form. Note how point D = (-3, -2) is the highest point for g(x). So the max for g(x) is y = -2

3 0
3 years ago
Read 2 more answers
PLZ HELP!!!!!!!<br>Solve for x​
Lunna [17]

Answer:

100

Step-by-step explanation:

hehe

6 0
3 years ago
Which function does the graph represent? What is the asymptote of the function?
Snowcat [4.5K]

Answer:

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5 0
2 years ago
4x – y = 7 3y – 12x = –21
Elis [28]

Answer:

y= 4x − 7 or 0=0

Step-by-step explanation:

4x−y+−4x=7+−4x

6 0
3 years ago
Read 2 more answers
I have some cheese. I used
hram777 [196]
<h3>Answer:     2500 grams</h3>

============================================

Work Shown:

A = amount of grams of cheese you had originally

B = (2/5)*A = amount of cheese you use up after day 1

C = (3/5)*A = amount of cheese you have left over after day 1

note how B and C add back up to 'A'.

This is because 2/5+3/5 = 5/5 = 1, so,

B+C = (2/5)A+(3/5)A = (2/5+3/5)A = 1*A = A

--------------

D = (2/5)*C = amount of cheese you use up after day 2

E = (3/5)*C = amount of cheese left over after day 2

the variables D and E add up to C

we are told that there are 900 grams of cheese left after day 2, so E = 900

--------------

E = (3/5)*C

(3/5)*C = E

(3/5)*C = 900 ... Plug in E = 900

3C = 900*5 .... multiply both sides by 5

3C = 4500

C = 4500/3 .... divide both sides by 3

C = 1500

This means you had 1500 grams of cheese after day 1

-------------

C = (3/5)*A

(3/5)*A = C

(3/5)*A = 1500 ... plug in C = 1500

3A = 1500*5 ... multiply both sides by 5

3A = 7500

A = 7500/3 .... divide both sides by 3

A = 2500

-----------

<h3>You started off with 2500 grams of cheese.</h3>

After day 1, you use up (2/5)*2500 = 1000 grams of cheese and have 2500-1000 = 1500 grams left over.

After day 2, you use up (2/5)*1500 = 600 grams of cheese and have 1500-600 = 900 grams left over.

The answer is confirmed.

6 0
3 years ago
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