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RideAnS [48]
3 years ago
6

$121.50 for working 18 hour shift? unit rate

Mathematics
1 answer:
yanalaym [24]3 years ago
4 0
To find the unit rate, divide 121.5/18

121.5/18 = 6.75

The unit rate is $6.75
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So use undistributive properyt]
ab+ac=a(b+c)
so factor 24a dadn 28 to find 'a' the common factor
24=2 times 2 times 2 times 3 tiems a
28=2 times 2 times 7
common one is 2 itmes 2=4
a=4
4(2 times3 times a)+4(7)=4(6a)+4(7)=4(6a+7)

7 0
3 years ago
Y=1/3x+4 going through the point (9,-2)
Art [367]
Substitute x=9 and y=-2 into equation,
Left hand side=-2
Right hand side=1/3(9)+4= 3+4=7

Because LHS doesn’t = with RHS, the point (9,-2) doesn’t satisfy with the equation

Therefore the point doesn’t go through y=1/3x +4.
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Which of the following best classifies a quadrilateral with coordinates A(8, 4), B(6, 0), C(3, 2), and D(7, 10)? Trapezoid Paral
LuckyWell [14K]

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4 0
2 years ago
Read 2 more answers
PLS HELP ILL GIVE BRAINLEST <br> 1/4 ÷ 3/8<br> divide. i need it in fraction form for an answer
Advocard [28]

Answer:

answere=2/3

Step-by-step explanation:

1/4 divide 3/8

First we will reciprocal

1/4 X 8/3

Now will simplify to lowest term

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6 0
2 years ago
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Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notic
Free_Kalibri [48]

The equation for the situation is y=200(\frac{2}{3})^{x}

It will take around 9 years for her to have around 5 sheep

Step-by-step explanation:

The exponential decay growth/decay equation is y=a(b)^{x} , where

  • a is the initial value
  • b is the growth/decay factor
  • If b > 1, then it is a growth factor
  • If 0 < b < 1, then it is a decay factor

Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notices that the population is two-thirds of the previous year

∵ The population is decreased

∴ The equation is decay

∵ The population is two-thirds of the previous year

∴ The decay factor is \frac{2}{3}

∵ She starts with an initial 200 sheep

∴ the initial value is 200

∵ The decay equation is y=a(b)^{x} , where y represent the

   population in x years

∵ a = 200

∵ b = \frac{2}{3}

∴ y=200(\frac{2}{3})^{x}

The equation for the situation is y=200(\frac{2}{3})^{x}

∵ The population after x years is around 5 sheep

- Substitute y by 5 to find x

∵ 5=200(\frac{2}{3})^{x}

- Divide both sides by 200

∴ 0.025=(\frac{2}{3})^{x}

- Insert ㏒ for both sides

∴ log(0.025)=log(\frac{2}{3})^{x}

∴ log(0.025)=xlog(\frac{2}{3})

- Divide both sides by log(\frac{2}{3})

∴ 9.098 = x

∴ x is around 9 years

It will take around 9 years for her to have around 5 sheep

Learn more:

You can learn more about the equation  in brainly.com/question/10666510

#LearnwithBrainly

8 0
3 years ago
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