Write the expression (4x-2)×6(2x+7) in the standard form of a quadratic expression ax^{2}+bx+c. What are the values of the coeff
icients of each term and the constant term.
find the answer for a, b, and c
1 answer:
<span>(4x-2)×6(2x+7) =
</span>
(4x-2) <span>× 12x + 42 =
48x^2 -24x + 168x -84 = 0
</span>
<span>48x^2 +144x -84 = 0
a = 48 b = 144 and c = -84
and the solution is
x1=.5 and x2=-3.5
</span>
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Answer:
144
Step-by-step explanation:
8x12 = 96 and 4x12= 48 and 96+48= 144
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Answer:
I think: 0 = 3x + b or b = -3x + 0 or x = -b + 0/3 or 3 = -b + 0/x
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Step-by-step explanation:
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