The two real values that are not in the domain of the composition are x = 2 and x = -2.
<h3>
What two numbers are not in the domain of f°g?</h3>
Here we have:
f(x) = 1/x
g(x) = x^2 - 4
The composition is:
f°g = f(g(x)) = 1/(x^2 - 4)
The two values that are not in the domain are the values of x such that g(x) = 0, because we can't divide by zero.
g(x) = 0 = x^2 - 4
4 = x^2
±√4 = x
±2 = x
So g(x) = 0 when x = 2 or x = -2, so these are the two real values that are not in the domain of f°g.
If you want to learn more about domains:
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Answer:
19 in = 48.26 cm
Step-by-step explanation:
Devide 19 by 2.54 you get 48.26 cm
( 2x − 27 ) ( −x + 15 )
= ( 2x + −27 ) ( −x + 15 )
= ( 2x ) ( −x ) + ( 2x ) ( 15 ) + ( −27 ) ( −x ) + ( −27 ) ( 15 )
= −2x^2 + 30x + 27x − 405
= −2x^2 + 57x − 405
It would be perpendicular
Answer:
- <em>To solve these first swap x and y, solve for y and name it inverse function</em>
3. <u>y = -8x + 2</u>
- x = -8y + 2
- 8y = -x + 2
- y = -x/8 + 2/8
- y = -(18)x + 1/4
f⁻¹(x) = -(18)x + 1/4
-----------------------------------------
4.<u> y = (2/3)x - 5</u>
- x = (2/3)y - 5
- (2/3)y = x + 5
- y = (3/2)x + (3/2)5
- y = 1.5x + 7.5
f⁻¹(x) = 1.5x + 7.5
-----------------------------------------
5. <u>f(x) = 2x² - 6</u>
- x = 2y² - 6
- 2y² = x + 6
- y² = 1/2x + 3
- y =
f⁻¹(x) =
-----------------------------------------
6. <u>y = (x - 3)²</u>
- x = (y - 3)²
= y - 3- y = 3 +
f⁻¹(x) = 3 +
