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ycow [4]
3 years ago
12

Caden took her basketball team out for dinner after their tournament the total cost for dinner was $120 she had a coupon for 30%

off of the total cost after the discount was taken off she decided to leave a 22% tip on the discounted total how much money did Caden end up spending for dinner and tip ?​
Mathematics
1 answer:
Dafna11 [192]3 years ago
6 0

so 120 - 39 is 80 then minus the basketball and you get fortyfor

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3.) SOLVE FOR X.
gayaneshka [121]

The value of x in the secants intersection is 1 units

The value of NM in the tangent and secant intersection is 51 units

<h3>How to find length when secant and tangent intersect?</h3>

The first question, two secant intersect outside the circle.

Therefore,

(6x + 8x)8x = (9 + 7)7

14x(8x) = 16(7)

112x² = 112

x² = 112 / 112

x = √1

x = 1

The second question, tangent and secant intersect,

Therefore,

(x + 3)² = (x - 3)(16 + x - 3)

(x + 3)² = (x - 3)(x + 13)

(x + 3)(x + 3) = (x - 3)(x + 13)

x² + 3x + 3x + 9 = x² + 13x - 3x - 39

x² + 9x + 9 = x² + 10x - 39

x² - x² + 9x - 10x = -39 - 9

-x = - 48

x = 48

NM = 48 + 3 = 51 units

learn more on secant and tangent here: brainly.com/question/12477905

#SPJ1

6 0
2 years ago
Michael read 135 pages in 1 1/2 hours, Select all of the rates that are equivalent to this rate
devlian [24]

The rates that are equivalent to this rate is 90 pages/hr

<h3>Rate of change</h3>

The rate is the number of pages Michael read in 1 hour.

If he read 135 pages in 1 1/2 hours then;

  • 135 pages = 1.5 hours

To determine the rate, we will have:

  • x = 1 hour

Divide both expressions:

135/x = 1.5/1

1.5x = 135

x = 135/1.5

x = 90

Hence the rates that are equivalent to this rate is 90 pages/hr

Learn more on rate here: brainly.com/question/119866

6 0
2 years ago
Need help please AsAp
Serga [27]

Answer:

B, the answer is B

4 0
3 years ago
Read 2 more answers
Suzanne ran 4.5 miles for the school fundraiser. She earned $2.40 per mile. How much money did she make?
pochemuha

Answer:

the answer is $10.

$2.40=1

n=4.5

= 4.5×2.40

=$10.80

7 0
3 years ago
Find the value(s) of c such that the area of the region bounded by the parabolae y=x^2−c^2 and y=c^2−x^2 is 4608.
alina1380 [7]
C is 12 and x is 3 and that would be your variables
7 0
3 years ago
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