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topjm [15]
3 years ago
5

Perform the indicated operation. -27 ÷ -9 -3 -18 -36 none of the above

Mathematics
1 answer:
Vlad [161]3 years ago
3 0

None of the above. The correct answer would be 3.

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A car is designed to last an average of 12 years with a standard deviation of 0.8 years. What is the probability that a car will
Scorpion4ik [409]
Due to the common probability formula I can solve that task. Refering to the task you gave, we have all the information we need. We solve it like that: \frac{10-12}{0.8} = -2.5; Probability(-2.5)=.0.00621; Probability = 0.621%
So the answer is the first option <span>0.621%</span>
5 0
3 years ago
Read 2 more answers
.hoi I need a lil help
mihalych1998 [28]

Answer:

10

Step-by-step explanation:

4+5=9 and 1/2+1/2 =1  so 9+1=10

6 0
3 years ago
Read 2 more answers
Which points are solutions to the system of inequalities shown below? Check all that apply.
Alexandra [31]
I: y<2*x
II: y<8
III: x>2

a: (5,3):
I: 3<2*5
3<10 ?yes
II: 3<8 ?yes
III: 5>2 ?yes
This is a solution

b: (6,0):
I: 0<2*6
0<12 ?yes
II: 0<8 ?yes
III: 6>2 ?yes
This is a solution

c: (3,3):
I: 3<2*3
3<6 ?yes
II: 3<8 ?yes
III: 3>2 ?yes
This is a solution

d: (1,-4):
I: -4<2*1
-4<2 ?yes
II: -4<8 ?yes
III: 1>2 ?no
This is not a solution

e: (4,-2):
I: -2<2*4
-2<8 ?yes
II: -2<8 ?yes
III: 4>2 ?yes
This is a solution

f: (5,9):
I: 9<2*5
9<10 ?yes
II: 9<8 ?no
This is not a solution

so a,b,c,e are solutions and d,f not
6 0
3 years ago
What is 16 tens + 4 ones
aalyn [17]
(16*0) + (4*1)
16*10 = 160
4*1 = 4
160 + 4
The answer is 164! :)

5 0
3 years ago
Read 2 more answers
A tire manufacturer warranties its tires to last at least 20,000 miles orâ "you get a new set ofâ tires." In itsâ experience, a
Y_Kistochka [10]

Answer:

Probability that a set of tires wears out before 20,000 miles is 0.1151.

Step-by-step explanation:

We are given that a tire manufacturer warranties its tires to last at least 20,000 miles or "you get a new set of tires." In its past experience, a set of these tires last on average 26,000 miles with S.D. 5,000 miles. Assume that the wear is normally distributed.

<em>Let X = wearing of tires</em>

So, X ~ N(\mu=26,000,\sigma^{2}=5,000^{2})

Now, the z score probability distribution is given by;

         Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = average lasting of tires = 26,000 miles

            \sigma = standard deviation = 5,000 miles

So, probability that a set of tires wears out before 20,000 miles is given by = P(X < 20,000 miles)

    P(X < 20,000) = P( \frac{X-\mu}{\sigma} < \frac{20,000-26,000}{5,000} ) = P(Z < -1.2) = 1 - P(Z \leq 1.2)

                                                                    = 1 - 0.88493 = 0.1151

Therefore, probability that a set of tires wears out before 20,000 miles is 0.1151.

4 0
3 years ago
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