0.034833091436865 This is the answer. Sorry but can't show work
To get the *percent increase* from week 1 to week 2, we calculate the change in distance from week 1 to week 2 (13.5 - 12.5 = 1 mile) over the week 1 distance (12.5 miles). Doing that, we find that Matthew increased his distance by
1/12.5 = 0.08, or 8%
We’re given that he’ll increase his distance by the same percentage from week 2 to 3, so to find his week 3 distance, we can find 8% of the week 2 distance and add that on. 8% of 13.5 miles is 0.08 x 13.5 = 1.08 miles, so by week 3, he’ll be running 13.5 + 1.08 = 14.58 miles.
Answer:
The probability of the tip to be more than 200 is 0.1.
Step-by-step explanation:
As per the given data
Amount of tip Number
0-20 200
20-50 100
50-100 75
100-200 75
200+ 50
____________________
Total= 500
So what is the probability of tip to be more than 200 is given as
From the table the value is 50 for the tip to be more than 200 where as the total occurrences are 500 so substituting values:
So the probability of the tip to be more than 200 is 0.1.
Answer:
p = 11.2
Step-by-step explanation:
The computation is shown below:
Data provided in the question
2.6(5.5p – 12.4) = 127.92
Now
Distributive Propertyis
14.3p - 32.24 = 127.92
Addition Property is
14.3p = 127.92 + 32.24
Division Property is
14.3p ÷ 14.3 = 160.16 ÷ 14.3
p = 11.2
We simply find the value of p by applying the distributive property, addition property, and the division property and the same is to be considered
