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Nikitich [7]
3 years ago
15

Optimization-

Mathematics
1 answer:
pishuonlain [190]3 years ago
5 0
Do you want a proof or just the answer?
The answer is: the square (2.5x2.5).
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A soccer ball manufacturer wants to estimate the mean circumference of soccer balls within 0.1 in. Determine the minimum sample
leva [86]

Answer:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (2)  

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(0.25)}{0.1})^2 =24.01  

So the answer for this case would be n=25 rounded up to the nearest integer  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)  

\sigma=0.25 represent the population standard deviation

n represent the sample size (variable of interest)  

Solution to the problem

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}  

The margin of error is given by this formula:  

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

And on this case we have that ME =0.1 and we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (2)  

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(0.25)}{0.1})^2 =24.01  

So the answer for this case would be n=25 rounded up to the nearest integer  

8 0
4 years ago
Can a triangle be formed if the side<br> lengths are 10, 23, and 10?
FinnZ [79.3K]

Answer:

No.

Step-by-step explanation:

No, because 23 > 10 + 10.

If any side is equal or greater than the sum of the other 2 sides no triangle can be drawn.

5 0
3 years ago
Read 2 more answers
An engineer is designing a runway for an airport. Several planes will use the runway and the engineer must design it so that it
swat32

Answer:

d=117.33 m

Step-by-step explanation:

Initial velocity of planes, u = 0 (because they are at rest)

Acceleration, a = 3.3 m/s²

Final take off speed, v = 88 m/s

We need to find the minimum allowed length for the runway. Let it is d. d will be the distance. It can be calculated using third equation of motion as follows :

v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}

Putting all the values, we get :

d=\dfrac{88^2-0^2}{2\times 33}\\\\d=117.34\ m

Hence, the minimum allowed length for the runway is 117.33 m.

3 0
3 years ago
I need help on number 6 plz!
expeople1 [14]

Woah that looks hard

8 0
3 years ago
I need an answer and explaination​
Dmitry_Shevchenko [17]
The answer for the question is 97
3 0
3 years ago
Read 2 more answers
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