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2 years ago

15

Please help me! Is So Thank You!

1 answer:

Arada [10]2 years ago

3 0

according to the graph y is 0 when x is -3

x is numbered by 2 so each line in the middle is the number between,

you can also find that if you have the equation, you simply just plug in -3 for x.

hope that helped! :)

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Solve 4 - 2(-5a - 10)=30 and justify each step

Sergeeva-Olga [200]

First you would do parenthesis according to the PEMDAS(Parenthesis, Exponents, Multiply, Divide, Add, Subtract) Rule

4 -2(-5a -10) = 30

4 + 10a + 20 = 30

Now you need to add 4 and 20 because they are on the same side

24 + 10a = 30

Now subtract 24 on both sides

24 + 10a = 30

-24. -24

10a = 6

Last divide 10 from both sides

10a/10. = 6/10

a= 6/10

Last simplify (optional but recommended)

a = 3/5 or 0.6

Hope this helped :)

A = 0.6

5 0

2 years ago

A basketball player made 17 out of 20 free throws at a practice. What percent of the free throws did the player miss?

s2008m [1.1K]

Answer:

he missed 97%

Step-by-step explanation:

subtract 17-20 to get 3 and subtract 3 from 100% to get 97%, then multiply 97 by 3

3 0

2 years ago

50 points.<br> Please help me write a rational function that fits this graph

garik1379 [7]

Answer:

Ok

Step-by-step explanation:

I will help you or maybe.

7 0

2 years ago

2x -3y=8 solve for y

brilliants [131]

$2x-3y=8\ \ \ \ \ \ |subtract\ 2x\\\\-3y=8-2x\ \ \ \ \ \ \ \ \ |:-3\\\\y=\frac{8-2x}{-3}$

5 0

2 years ago

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

4 0

2 years ago