The answer will be 2,400,000 <span>kg⋅m/s</span><span>2</span>
Answer
ω2=82.1 rpm
Explanation:
given required
m1=2.3 kg ω2=?
m2+m3=0.5kg
r1=10 cm
ω1=100 rpm
solution
Using the application of conservation of angular momentum we can solve as follows/
L before collision= L after collision
m1r²ω1=(m1+m2+m3)r²ω2
2.3 kg×0.1² m²×100 rpm=(2.3 kg+0.5 kg)×0.1²m²×ω2
2.3 rpm=0.028×ω2
ω2=82.1 rpm
Answer:
A. Conservation of energy.
Explanation:
Kirchhoff's loop rule is an example of conservation of energy.
The question is asking to describe and state and calculate what do the observer on the earth measure for the speed of the laser beam, and base on my research, the answer would be v = 1bc, I hope you are satisfied with my answer and feel free to ask for more
