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stira [4]
2 years ago
15

Which of these organs is an endocrine structure?

Physics
1 answer:
Gre4nikov [31]2 years ago
6 0

Answer: Actually three of them are. The ovaries, the uterus and fallopian tubes.

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A baseball pitcher throws a ball at 40 ms^-1. if the acceleration is approximately constant over a distance of 2 m, how large is
Reil [10]

We have the equation of motion v^2=u^2+2as, where v i the final velocity, u is the initial velocity, a is the acceleration and s is the displacement

Here final velocity, v = 40m/s

        Initial velocity, u = 0 m/s

        Displacement s = 2 m

Substituting 40^2=0^2+2*a*2\\ \\ a=400m/s^2

So the baseball pitcher accelerates at 400m/s^2 to release a ball at 40 m/s.

4 0
3 years ago
Help!!!! A loop of area 0.100 m^2 is oriented at 15.5 degree angle to a 0.500 T magnetic field. It rotates until it is at a 45.0
Nat2105 [25]

Answer:

Resulting Change in the Magnetic Flux =0.013\:Wb

Explanation:

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3 0
3 years ago
A solar reflector is made using 31 identical triangular-shaped mirrors, each having sides . What is the total surface area of th
Stels [109]

Complete Question

Question 18 (3 points) Solve the problem. (3 points) A solar reflector is made using 31 identical triangular-shaped mirrors, each having sides 2.4m, 2. 3m, 1.5 m. What is the total surface area of the reflector?

A) 33 m2  

B) 86 m2

C) 52 m2

D)  34 m2

Answer:

The value is  Area  =2.78 \   m^2

Explanation:

From the question we are told that

   The  sides are  a =  2.4 m

                             b  =  2.3 m

                             c  =  1.5 m

Generally the semi perimeter is mathematically represented as

           s = \frac { a + b  + c  }{2 }

=>       s = \frac { 2.4  + 2.3  + 1.5   }{2 }

=>       s =3.1  \  m

Generally the using Heron's  formula we have that the  surface are a is  mathematically represented as

            Area  =  \sqrt{S (S -  a) (S - b )(S - c ) }

=>         Area  =  \sqrt{3.1  (3.1  -   2.4) (3.1  -  2.3 )(3.1  -  1.5 ) }

=>        Area  =2.78 \   m^2

6 0
2 years ago
At t = 0 a grinding wheel has an angular velocity of 24.0 rad/s. It has a constant angular acceleration of 30.0rad/s2 until a ci
kozerog [31]

Answer:

θ=108rad

t =10.29seconds

α=-8.17rad/s²

Explanation:

Given that

At t=0, Wo=24rad/sec

Constant angular acceleration =30rad/s²

At t=2, θ=432rad as it try to stop because the circuit break

Angular motion

W=Wo+αt

θ=Wot+1/2αt²

W²=Wo²+2αθ

We need to find θ between 0sec to 2sec when the wheel stop

a. θ=Wot+1/2αt²

θ=24×2+1/2×30×2²

θ=48+60

θ=108rad.

b. W=Wo+αt

W=24+30×2

W=84rad/s

This is the final angular velocity which is the initial angular velocity when the wheel starts to decelerate.

Wo=84rad/sec

W=0rad/s, because the wheel stop at θ=432rad

Using W²=Wo²+2αθ

0²=84²+2×α×432

-84²=864α

α=-8.17rad/s²

It is negative because it is decelerating

Now, time taken for the wheel to stop

W=Wo+αt

0=84-8.17t

-84=-8.17t

Then t =10.29seconds.

a. θ=108rad

b. t =10.29seconds

c. α=-8.17rad/s²

3 0
3 years ago
Which of the following can be an effect of a volcanic winter? select the two correct answers
Marysya12 [62]

it is B. Famine and C. Climate cooling

8 0
3 years ago
Read 2 more answers
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