All categories

3 years ago

What is the value of the function f(x)=20x when x=0.25?

Mathematics

1 answer:

matrenka [14]3 years ago

6 0

20 times (0.25) equals 5

You might be interested in

Please help me with this question ASAP

Kaylis [27]

Answer:The distributive property of equality

Step-by-step explanation:the 8 was distributed into the -6

7 0

3 years ago

Help pls.preparing for my term exam

aniked [119]

Answer:

Step-by-step explanation:

she will have 2 arangments of one rose and two daisies.

5 0

3 years ago

Read 2 more answers

G(x)=-3x+2 and g(x)=-1, find x

Zinaida [17]

Answer:

x=1

Step-by-step explanation:

7 0

3 years ago

Select the answer with the correct number of significant figures for each calculation. (6.022 × 10^23) × 2.58 = 1.55 × 10^24 1.5

maxonik [38]

Answer:

1.55 × 10^24

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

One hundred items are simultaneously put on a life test. Suppose the lifetimes

romanna [79]

Answer:

a) $\mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}$

b) $\mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}$

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( $i-1$ )st and the $ith$ failures. Then, the $T_{i}$ are independent with $\mathrm{T}_{\mathrm{i}}$ being exponential with rate $\frac{(101-i)}{200} .$

Therefore,

a) $E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]$

$=\sum_{i=1}^{5} \frac{200}{101-i}$

$\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}$

$b)$

The variance is given by, $\mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]$

$\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}$

7 0

3 years ago