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3 years ago

Kim's puppy gained 3/8 pound each week for 4 weeks altogether how much weight did the puppy gain during the 4 weeks

1 answer:

3 0

<span> 3/8 each week for 4 weeks 3/8 times 4=3/8 times 4/1=12/8=6/4=3/2=1 and 1/2 gained 3/2 or 1 and 1/2 pounds

I Think I Got It Wrong So I'm Sorry If I Did =C
I Hope It Helped =D</span>

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Help me with this questionnnnn

svetlana [45]

Answer:

3:9=4

Step-by-step explanation:

That is my answer

please brainliest

6 0

3 years ago

Find the sum of the first 12 terms of the sequence 512, 256, 128, … This is infinite series notation, the answer is NOT 896...

postnew [5]

Answer:

1023.75

Step-by-step explanation:

The sum of a geometric sequence is

sum = a( 1 - r^n) / (1-r)

where a is the first term r is the common ratio and r^n is the nth term

We need to find the common ratio

r = 256/512 = 1/2

sum = 512 ( 1 - 1/2^12) / ( 1-1/2)

=512( 1-.000244141) / (.5)

=512(.999755859) /.5

=1023.75

7 0

3 years ago

Read 2 more answers

What is the substitution of<br><img src="https://tex.z-dn.net/?f=%28x%20%20-%20%201%29%5E%7B2%7D%20" id="TexFormula1" title="(x

Ber [7]

Answer:

x should be 1

I think if you substitute it will just be the index 2 that remains , not sure though .You should probably ask your teacher for assistance

5 0

3 years ago

Solve the separable differential equation dtdx=x2+164 and find the particular solution satisfying the initial condition x(0)=9

maria [59]

$\dfrac{dt}{dx} = x^2 + \frac{1}{64} \Rightarrow\ dt = \left(x^2 + \frac{1}{64}\right)dx \Rightarrow \\ \\ \displaystyle \int 1 dt = \int \left(x^2 + \frac{1}{64}\right)dx \Rightarrow \\ t = \dfrac{x^3}{3} + \frac{x}{64} + C$

C = 9 because all the x terms go away.

$t = \dfrac{x^3}{3} + \dfrac{x}{64} + 9$

3 0

3 years ago

How would I figure out a linear equation with two plot points with fractions? (1/3(6),3) and (1/2(19),-2) are my two plot points

murzikaleks [220]

Answer: $m=\frac{-30}{79},\ y=5.40$

Step-by-step explanation:

Given

Points are $\left(6\frac{1}{3},3\right),\ \left(19\frac{1}{2},-2\right)$

Convert mixed numeral to fraction

$\left(6\frac{1}{3},3\right)\Rightarrow \left(\dfrac{19}{3},3\right)\\\\\left(19\frac{1}{2},-2\right)\Rightarrow \left(\dfrac{39}{2},-2\right)$

Slope of the line is

$\Rightarrow m=\dfrac{3-(-2)}{\dfrac{19}{3}-\dfrac{39}{2}}\\\\\Rightarrow m=\dfrac{5}{\dfrac{38-117}{6}}\\\\\Rightarrow m=\dfrac{-30}{79}$

Equation of line

$\Rightarrow \dfrac{y-3}{x-\dfrac{19}{3}}=\dfrac{-30}{79}\\\\\text{for y-intercept, put x=0}\\\\\Rightarrow \dfrac{y-3}{0-\dfrac{19}{3}}=\dfrac{-30}{79}\\\\\Rightarrow y-3=\dfrac{190}{79}\\\\\Rightarrow y=3+2.40\\\Rightarrow y=5.40$

3 0

3 years ago