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aleksklad [387]

2 years ago

11

Which is the principal value of \sin^{-1}\left(0.43\right)sin −1 (0.43)sine, start superscript, minus, 1, end superscript, left

parenthesis, 0, point, 43, right parenthesis?

1 answer:

scoundrel [369]2 years ago

7 0

Answer:

The principal value of $\sin^{-1}\left(0.43\right)$ is 0.44.

Step-by-step explanation:

The given expression is

$\sin^{-1}\left(0.43\right)$

We need to find the principal value of $\sin^{-1}\left(0.43\right)$ .

Using calculator we get

$\sin^{-1}\left(0.43\right)=0.444492776936$

$\sin^{-1}\left(0.43\right)\approx 0.44$

Therefore the principal value of $\sin^{-1}\left(0.43\right)$ is 0.44.

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The University of Washington claims that it graduates 85% of its basketball players. An NCAA investigation about the graduation

Nonamiya [84]

Probabilities are used to determine the chances of events

The given parameters are:

Sample size: n = 20
Proportion: p = 85%

<h3>(a) What is the probability that 11 out of the 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 11) = ^{20}C_{11} \times (85\%)^{11} \times (1 - 85\%)^{20 -11}$

This gives

$P(x = 11) = 167960 \times (0.85)^{11} \times 0.15^{9}$

$P(x = 11) = 0.0011$

Express as percentage

$P(x = 11) = 0.11\%$

Hence, the probability that 11 out of the 20 would graduate is 0.11%

<h3>(b) To what extent do you think the university’s claim is true?</h3>

The probability 0.11% is less than 50%.

Hence, the extent that the university’s claim is true is very low

<h3>(c) What is the probability that all 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 20) = ^{20}C_{20} \times (85\%)^{20} \times (1 - 85\%)^{20 -20}$

This gives

$P(x = 20) = 1 \times (0.85)^{20} \times (0.15\%)^0$

$P(x = 20) = 0.0388$

Express as percentage

$P(x = 20) = 3.88\%$

Hence, the probability that all 20 would graduate is 3.88%

<h3>(d) The mean and the standard deviation</h3>

The mean is calculated as:

$\mu = np$

So, we have:

$\mu = 20 \times 85\%$

$\mu = 17$

The standard deviation is calculated as:

$\sigma = np(1 - p)$

So, we have:

$\sigma = 20 \times 85\% \times (1 - 85\%)$

$\sigma = 20 \times 0.85 \times 0.15$

$\sigma = 2.55$

Hence, the mean and the standard deviation are 17 and 2.55, respectively.

Read more about probabilities at:

brainly.com/question/15246027

8 0

2 years ago

SOLVE EQUATION BY TAKING SQUARE ROOTS.<br> -100+81a^2=0

IceJOKER [234]

Answer:

a = ±10/9

Step-by-step explanation:

$-100+81a^2=0\\81a^2=100\\a^2=\frac{100}{81}\\\sqrt{a^2}=\sqrt{\frac{100}{81} }\\a=10/9\\a=-10/9$

7 0

2 years ago

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If x represents a number, does 2/5 times x always represent 40% of that number?

marusya05 [52]

Answer:

Yes, it always represent 40% of that number.

Step-by-step explanation:

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2 years ago

The domain of both f(x) = x - 6 and g(x) = x + 6 is all real numbers. What is the domain of h(x) = f(x)/g(x)?

arlik [135]

This is a quotient (division) of two functions we must be concerned with the fact that division by zero is undefined.

Since g(x) is in the divisor position, it cannot equal 0.
$x+6 \neq 0$
$x \neq -6$ Subtract 6 from both sides to solve.
So the domain is all real numbers except -6
Set notation {x | x ∈ R, x ≠ -6}
Interval notation (-∞,-6)∪(-6,∞)

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2 years ago

Vincent rolls two dice. What is the probability his results are a multiple of four or the

Afina-wow [57]

Answer:

Sample space: 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 3.1, 3.2, 3.3, 3.4, 3.5, 3.6, 4.1, 4.2, 4.3, 4.4, 4.5, 4.6, 5.1, 5.2, 5.3, 5.4, 5.5, 5.6, 6.1, 6.2, 6.3, 6.4, 6.5, 6.6.

So the mutiples are 1.3, 2.2, 2.6, 3.1, 3.5, 4.4, 5.3, 6.2, and 6.6

Greather than 6 is 1.6, 2.5, 3.4, 3.6, 4.3, 4.5 4.6, 5.2, 5.4, 5.5, 5.6, 6.1, 6.3, 6.4, and 6.5.

So the prop is 24/36 or 2/3=66%

4 0

2 years ago