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3 years ago

Which figure best represents a kite?

Mathematics

1 answer:

suter [353]3 years ago

4 0

Answer:

4th one: A kite is the answer.

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Heellllppppppppppppp

daser333 [38]

Answer:

x = $\frac{1}{5}$ , y = 6

Step-by-step explanation:

5x + y = 7 → (1)

20x + 2 = y → (2)

Substitute y = 20x + 2 into (1)

5x + 20x + 2 = 7

25x + 2 = 7 ( subtract 2 from both sides )

25x = 5 ( divide both sides by 25 )

x = $\frac{5}{25}$ = $\frac{1}{5}$

Substitute this value into (2) and evaluate

20( $\frac{1}{5}$ ) + 2 = y

4 + 2 = y , so

y = 6

8 0

3 years ago

Read 2 more answers

The height, h, of a falling object t seconds after it is dropped from a platform 300 feet above the ground is modeled by the fun

Svetllana [295]

H(x)=-16t^2+300

The average rate is the change in h divided by the change in t, mathematically:

r=(h(3)-h(0))/(t2-t1), in this case:

r=(-16*9+300-0-300)/(3-0)

r=-144/3

r= -48 ft/s

5 0

3 years ago

Read 2 more answers

The bus driver made 6 stops on his way into town. No passengers left the bus. By stop 3, there were 9 passengers on the bus. How

borishaifa [10]

There were 9 passengers on the bus because no passengers got off during the six stops and the fifth stop is within that.

4 0

3 years ago

Your cell phone plan is by the minute. each minute of use cost $0.10. create a relation that represents the amount spent, A, per

Dmitriy789 [7]

Answer:

Talking 65 minutes, $ 6.50 must be paid.

Step-by-step explanation:

Since your cell phone plan is by the minute, and each minute of use cost $ 0.10, to create a relation that represents the amount spent, A, per minute, m, of call time, and then use the relation to find the amount spent if you talk 65 minutes, the following calculations must be performed:

0.10 x M = A

0.10 x 65 = A

6.50 = A

Thus, talking 65 minutes, $ 6.50 must be paid.

3 0

3 years ago

A sample of 15 commuters in Chicago showed the average of the commuting times was 33.2 minutes. If s = 8.3 minutes, find the 95%

OleMash [197]

Answer:

The 95% confidence interval of the true mean.

(29.4261 ,36.9739)

Step-by-step explanation:

Step :- (i)

Given sample size 'n' =15

sample of the mean x⁻ = 33.2

The standard deviation of the sample 'S' = 8.3

95% of confidence intervals

$(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )$

Step:-(ii)

The degrees of freedom γ=n-1 = 15-1=14

The tabulated value t = 1.761 at 0.05 level of significance.

now substitute all possible values, we get

$(33.2 - 1.761\frac{8.3}{\sqrt{15} } ,33.2+ 1.761\frac{8}{\sqrt{15} } )$

After calculation , we get

(33.2-3.7739 , 33.2+3.7739

(29.4261 ,36.9739)

Conclusion:-

the 95% confidence interval of the true mean.

(29.4261 ,36.9739)

8 0

3 years ago