Answer:
I think it's A AND C. The diameter is just the radius multiplied by 2 at the end of the day.B is just wrong.
Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
Answer:
2√14
Step-by-step explanation:
√56
√2^2 x 14
√2^2 √14
2√14
9514 1404 393
Answer:
see attachments for a table and graph
Step-by-step explanation:
I find it convenient to use a graphing calculator or spreadsheet to do repetitive computations reliably.
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Your specific question asks for h(0):
h(0) = -|0 +2| +1 = -2 +1
h(0) = -1
You may want to check your other table values.
first get all variables on the same side, then use elimination to solve.
x = -3
y = -11