Answer:
use pythagoras theorem to solve ur problem.
Answer:
128√5/3 mm³
Step-by-step explanation:
Since we are not told what to find, we can as well look for the volume of the pyramid
Volume of a square pyramid: V = (1/3)a²h
a is the side length of the square
h is the height of the pyramid
Given
a = 8mm
l² = (a/2)² + h²
l² = (a/2)² + h²
6² = (8/2)² + h²
h² = 6² - 4²
h² = 36 - 16
h² = 20
h = √20
Volume of a square pyramid = (1/3)*8²*√20
Volume of a square pyramid = 1/3 * 64 * 2√5
Volume of a square pyramid = 128√5/3 mm³
Make a drawing with a right triangle.
The opposite side, y, is the height of the dam less 1.65 m
The base or adjacent side is 90 m
The angle between the two sides is 90 m.
Then tan (26) = y / 90
y = 90 tan(26) = 90 (0.4877) = 43.90 m
The height of the dam is 43.90m + 1.65m = 45.55 m
13-11 9/20 = 1 11/20 sooo G
Answer:
3 cm
Step-by-step explanation:
The ratio of areas of similar figures is the square of the ratio of linear dimensions. That means the ratio of linear dimensions is the square root of the area ratio. The ratio of the smaller triangle dimensions to the larger is then ...
k = √((8 cm^2)/(18 cm^2)) = √(4/9) = 2/3
Then the corresponding side of the smaller triangle is ...
... k · (4.5 cm) = (2/3)·(4.5 cm) = 3 cm
