There's more than one way to combine them really
but an obvious one will be
![\bf \begin{array}{llll} h(x)&=&(f\circ g)(x)\\\\ &&\sqrt[3]{7x+1}\\\\ &&\sqrt[3]{g(x)}\leftarrow \begin{array}{llll} f(x)=\sqrt[3]{x }\\\\ g(x)=7x+1 \end{array} \end{array}\\\\ -----------------------------\\\\ (f\circ g)(x)\iff f[\quad g(x)\quad ]=\sqrt[3]{g(x)}\implies f[\quad g(x)\quad ]=\sqrt[3]{7x+1}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bllll%7D%0Ah%28x%29%26%3D%26%28f%5Ccirc%20g%29%28x%29%5C%5C%5C%5C%0A%26%26%5Csqrt%5B3%5D%7B7x%2B1%7D%5C%5C%5C%5C%0A%26%26%5Csqrt%5B3%5D%7Bg%28x%29%7D%5Cleftarrow%20%0A%5Cbegin%7Barray%7D%7Bllll%7D%0Af%28x%29%3D%5Csqrt%5B3%5D%7Bx%20%7D%5C%5C%5C%5C%0Ag%28x%29%3D7x%2B1%0A%5Cend%7Barray%7D%0A%5Cend%7Barray%7D%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0A%28f%5Ccirc%20g%29%28x%29%5Ciff%20f%5B%5Cquad%20g%28x%29%5Cquad%20%5D%3D%5Csqrt%5B3%5D%7Bg%28x%29%7D%5Cimplies%20%20f%5B%5Cquad%20g%28x%29%5Cquad%20%5D%3D%5Csqrt%5B3%5D%7B7x%2B1%7D)
but an obvious one will be
Each class at Greenville school has 22 children enrolled.the school has 24 classes how many children are enrolled at Greenville
2 answers:
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Answer:
Step-by-step explanation:
We are given this function for the height (h) after t seconds:
Seconds is t and we want to find the height after 1.5 seconds. Plug 1.5 in for t.
Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.
Solve the exponent first.
- (1.5)²= 1.5*1.5=2.25
Multiply.
Add.
This is already rounded to the nearest tenth, so it is the answer.
After 1.5 seconds, the basketball is at a height of 7.5 feet.
Answer:
Step-by-step explanation:
Hello There!
To solve for the area of this figure we need to split the figure into 3 different parts:
A rectangle with a length of 9 ft and a width of 7 ft
a rectangle with a width of 9ft + 7ft and a length of 25 ft
a rectangle with a width of 18 ft and a length of 22 ft
To find the area of a rectangle we use the formula
where w = width and l = length
for the first one we plug in the values
A = 9 * 7
9 * 7 = 63 so the area of the smallest rectangle is 63ft²
Now lets find the area of the larger rectangle
The dimensions are l = 25 ft and w = 9 + 7 (16 ft)
Now we can plug in the values into the area formula
A = 16 * 25
16*25=400 so the area of the larger rectangle is 400 ft²
Now lets find the area of the last rectangle
The dimensions are l = 22 ft and w = 18 ft
now lets plug in the values to the formula
A = 22 * 18 =396
so the area of the last rectangle is 396 ft²
Finally we want to add all of the areas together
396 + 400 + 63 = 859
So the area of the figure is 859 ft²