C = 2m^2 + m
D = 2 - 6m + 2m^2
2C = 2(2m^2 + m) = 4m^2+2m
2D = 2(2-6m+2m^2) = 4-12m+4m^2
2C - 2D =
4m^2+2m-(4-12m+4m^2) =
4m^2+2m-4+12m-4m^2 =
0m^2 + 14m -4 =
14m - 4
Answer:
14.285% or 14.3% if rounded to the nearest one decimal place.
Step-by-step explanation:
4 ÷28 × 100
Answer:
The correct answer is True.
Step-by-step explanation:
Altitude: vertical distance either between the top and bottom of something or between a base and something above it.
Juan's least integer scores in both tests will be 85 and 100 respectively.
- Test average of his two scores is atleast 92
Let :
- Score on test 1 = b
- Score on test 2 = b + 15
Average score can be related thus:
- (Sum of score ÷ number of test) ≥ 92
- (b + b + 15) ÷ 2 ≥ 92
- (2b + 15) ÷ 2 = 92
- 2b + 15 = 184
- 2b = 184 - 15
- 2b = 169
- b = 169 ÷ 2
- b = 84.5
Therefore, since both scores are integers, his least scores on both tests will be ::
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