Answer:
Time t = 2 seconds
It will reach the maximum height after 2 seconds
Completed question;
Amir stands on a balcony and throws a ball to his dog who is at ground level. The ball's height, in meters above the ground, after t seconds that Amir has thrown the ball is given by:
H (t) = -(t-2)^2+9
many seconds after being thrown will the ball reach its maximum height?
Step-by-step explanation:
The equation of the height!
h(t) = -(t-2)^2 + 9 = -(t^2 -4t +4) + 9
h(t) = -t^2 +4t -4+9
h(t) = -t^2 + 4t +5
The maximum height is at dh/dt = 0
dh/dt = -2t +4 = 0
2t = 4
t = 4/2 = 2
Time t = 2 seconds
It will reach the maximum height after 2 seconds
Answer:
b = -30
Step-by-step explanation:
-b/5 - 27 = -21
~Add 27 to both sides
-1/5b = 6
~Multiply -5 to both sides
b = -30
Best of Luck!
Area = base * altitude = 2 * 2.9 = 5.8 cm^2
Answer:
scale factor = 5
Step-by-step explanation:
To determine the scale factor calculate the ratio of corresponding sides of the enlargement to the original, that is
scale factor =
=
= 5
-1 is the answer to your question