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Wewaii [24]
4 years ago
6

How do u solve this?

Mathematics
1 answer:
vlabodo [156]4 years ago
4 0

\text{The formula of an area of a triangle:}\\\\A_\triangle=\dfrac{1}{2}bh\\\\b-base\\h-height\\----------------------\\\\\text{We have}\\\\b=41\dfrac{1}{2}ft=\dfrac{41\cdot2+1}{2}ft=\dfrac{83}{2}ft\\\\h=36ft\\\\\text{Substitute:}\\\\A_\triangle=\dfrac{1}{2}\left(\dfrac{83}{2}\right)(36)=\left(\dfrac{83}{\not4_1}\right)(36\!\!\!\!\!\!\diagup^9)=(83)(9)=747\ ft^2\\\\\\Answer:\ \boxed{A_\triangle=747\ ft^2}

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Answer:

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Step-by-step explanation:

See the diagram attached below which describes and represents the information given to us.

The tangents are PA and PB.

Tangents form right angle with the radius of a circle, therefore:

<OBP = <OAP = 90°

Therefore ∆OBP is a right triangle.

m<APO = m<BPO = ½(60) = 30°

Thus, in ∆OBP,

Reference angle = 30°

Side length opposite to reference angle = 12 ft

Adjacent length = length of tangent PB

Apply trigonometric function TOA, to find PB:

Tan 30 = Opp/Adj

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PB × Tan 30 = 12

PB = 12/Tan 30

PB = 20.7846097 ≈ 20.7 ft (nearest tenth)

Length of each segment = 20.7 ft

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Answer:

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Step-by-step explanation:

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Thus, 1/22 is the solution.

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