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stira [4]
3 years ago
14

A mine elevator was at a depth of -120 feet. After 15 seconds, the mine elevator was at a depth of -30 feet. Which expression sh

ows how to find the speed of the mine elevator in feet per second?
Mathematics
1 answer:
KonstantinChe [14]3 years ago
8 0
-120 + -30 = 90. 90/15 = 6
Answer ; 6mph
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I understand the switching of positive and negative signs but I don’t understand how to get to the next step which is the answer
Finger [1]
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now the same thing

let's say n=1

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3 years ago
What is 2 to the power of 4/3 equal to
Reika [66]

Answer:

<h2><u>E</u><u>k</u>sponent</h2>

\sf{ \large{ \boxed{ \red{ {a}^{ \frac{n}{m}  }  =  \sqrt[m]{ {a}^{n} } } } }}

\sf{ {2}^{ \frac{4}{3} } }

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4 0
2 years ago
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wariber [46]

Answer:

n \geq  -\frac{-29}{28}

Step-by-step explanation:

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4 years ago
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statuscvo [17]

Answer: The answer is \textup{The other root is }\dfrac{8}{3}~\textup{and}q=40.Step-by-step explanation:  The given quadratic equation is[tex]3x^2+7x-q=0\\\\\Rightarrow x^2-\dfrac{7}{3}x-\dfrac{q}{3}=0.

Also given that -5 is one of the roots, we are to find the other root and the value of 'q'.

Let the other root of the equation be 'p'. So, we have

p-5=-\dfrac{7}{3}\\\\\\\Rightarrow p=5-\dfrac{7}{3}\\\\\\\Rightarrow p=\dfrac{8}{3},

and

p\times(-5)=-\dfrac{q}{3}\\\\\\\Rightarrow \dfrac{8}{3}\times 5=\dfrac{q}{3}\\\\\\\Rightarrow q=40.

Thus, the other root is \dfrac{8}{3} and the value of 'q' is 40.

3 0
3 years ago
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alexdok [17]
The answer is c: 0,6
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3 years ago
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