A weak acid base pair that regulates pH is called a ?

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago

A rhombus has diagonals of 10cm and 6cm. Find the angles of the rhombus and its area.

Marrrta [24]

Answer:

area =length ×breath =10×6=60

3 0

3 years ago

Could y’all help me out with this?

Aneli [31]

Answer:

M' (5,-1)

D' (5,1)

A' (3,4)

W' (4,-1)

Step-by-step explanation:

We want to find the coordinates of Quadrilateral MDAW with vertices M(-1, 5), D(1,5), A(4,3), and W(-1,4) after a reflection across y = x.

We can find these coordinates by following the following rule:

Reflection over y = x rule : ( x , y ) ---> ( y , x )

Explanation of rule: Simply swap the places of the x and y values.

Applying rule to given coordinates:

M(-1,5) -----> swap x and y values -----> M'(5,-1)

D(1,5) ----> swap x and y values -----> D'(5,1)

A(4,3) -----> swap x and y values -----> A'(3,4)

W(-1,4) -----> swap x and y values -----> W'(4,-1)

So the coordinates of Quadrilateral MDAW after a reflection over the y = x line are M'(5,-1) , D'(5,1) , A'(3,4) , W'(4,-1)

For more validation, refer to the attached image

4 0

3 years ago

katie bought 4 sweaters that each cost the same amount and 1 skirt that costs 20$. The items she bought cost a total of 160$ bef

Alika [10]

Hello, in order to solve this you first need to take $20 subtracted from 160 that leaves you with 140 next because she bought 4 sweaters you need to divide your remaining cash spent by 4 to get a total of $35 a sweater.

I hope this is what you were looking for, have a great day!

8 0

3 years ago

Could someone please explain how to plot the x-intercept of the first equation and what the answer would be?

Elis [28]

Answer:

You would start in the middle of the number line, move right to positive 4x then move up 2 units to land right in line with 2y this is where your plot would be.

Step-by-step explanation:

Hope this helps mark brainliest please!

4 0

3 years ago